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3 years ago

For what x-values is the graphed function decreasing?

Mathematics

1 answer:

Lapatulllka [165]3 years ago

5 0

Answer:

Given function is decreasing for all x-values , except 4.

Step-by-step explanation:

We are given with a graph of the function and we are asked to find x-values for which function is decreasing.

We will say a function is decreasing If as x increases(from left to right) y decreases(goes down).

The given graph has 2 regions till x=4 and after x=4

Till x=4, if we see the graph from left to right, graph is going down, which means it is decreasing.

After x=4 also, as x goes from left to right, graph is going down, which means it is decreasing after x=4 also.

Hence the given function is decreasing for all x-values except x=4.

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Using the table, we will see that the function is:

t(l) = 3*l

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Here we only have a table to work with, so we need to use that.

In the table, we can see the pairs:

t(1) = 3
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From that we can conclude that the function will be:

t(l) = 3*l

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2 years ago

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The answer is A. 2, -2

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3 years ago

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Which of the following equations will produce the graph shown below?

melisa1 [442]

The graph is a circle, centered at the origin, with radius=4.

We know that we can write the equation of a circle with radius r and center (a,b) as :

$(x-a)^2+(y-b)^2=r^2$ .

Thus, substituting (a, b) with (0, 0) and r with 4, we have:

$x^2+y^2=16$ .

The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:

$x^2+y^2=16\\\\x^2+y^2-16=0\\\\2(x^2+y^2-16)=0$ ,

we would still have the same roots.

Thus, the equation of the circle can be written as :

$2x^2+2y^2=32$ .

Answer: B

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3 years ago

Read 2 more answers