Probably A I am not really sure I am trying sorry if it is wrong
Answer is: B
Step-by-step explanation: correct answer is B
b
2
−a
2
Given, acotθ+bcscθ=p
bcotθ+acscθ=q
⇒p
2
−q
2
=(p−q)(p+q)
=[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]
=[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]
=(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)
=(a
2
−b
2
)(cot
2
θ−csc
2
θ)
=(−1)(a
2
−b
2
)[∵csc
2
θ−cot
2
θ=1]
=(b
2
−a
2
)
I hope this helps you
radius=diameter/2
radius=1,5/2
radius=0,75
Area=pi. r^2
Area=3,14. (0,75)^2
Area=1,76
Answer:
2x +5y = -15
Step-by-step explanation:
We need to find the slope
m = (y2-y1)/(x2-x1)
= (-7--1)/(10- -5)
= (-7+1)/(10+5)
-6/15
-2/5
The point slope form
Y+7=
-2/5 (x - 10).
Distribute
y + 7 = -2/5x + 4
Add 2/5 x to each side
2/5x +y +7 = 4
Subtract 7 from each side
2/5x +y = -3
Multiply each side by 5
5(2/5x +y) = -3*5
2x +5y = -15
This is standard form Ax + By = C where A is a positive integer
Teds minimum grade he needs on his third test is 65
85 + 60 + 65 = 210
210 divide by three (as there are three tests) = 70
