Answer:
fH = - 3,255.7 kJ/mol
Explanation:
Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.
Qsystem + Qcombustion = 0
Qsystem = heat capacity*ΔT
10000*(25.000 - 20.826) + Qc = 0
Qcombustion = - 41,740 J = - 41.74 kJ
So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:
n = mass/molar mass = 1/ 78
n = 0.01282 mol
fH = -41.74/0.01282
fH = - 3,255.7 kJ/mol
Answer:
What are the advantages of titration?
Titrimetric analysis commonly referred to as volumetric analysis offers distinct advantages over cumbersome gravimetric methods:
Speed of analysis.
Instantaneous completion of reactions.
Greater accuracy due to minimization of material loss involved in decanting, filtration, precipitation or similar operations.
Explanation:
Disadvantages
It is a destructive method often using up relatively large quantities of the substance being analysed.
It requires reactions to occur in a liquid phase, often the chemistry of interest will make this inappropriate.
It can produce significant amounts of chemical waste which has to be disposed of.
It has limited accuracy.
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Answer:Score” scatter plot shows an example of a positive relationship—as one variable increases, so does the other. The points in this type of scatter plot tend to go “uphill” from left to right
Explanation:Score” scatter plot shows an example of a positive relationship—as one variable increases, so does the other. The points in this type of scatter plot tend to go “uphill” from left to right
Answer:
I think its 1.40M Na^+ we convert to Na3PO4 which means we need 1.40M x (1 mole Na3PO4/3 mol Na^+) = 1.40 x 1/3 = 0.467 M Na3PO4.
Explanation:
