Answer:
Step-by-step explanation:
Combine like terms: Like terms have same variable with same power and to combine the like terms, add/subtract the co efficient of the variables.
<h3>Perimeter:</h3>
Perimeter = sum of all sides
a) Perimeter of ΔABC = AB + BC + CA
= x + 14 + x + 14 + x + 14
= x + x + x + 14 + 14 + 14 {Combine like terms}
= 3x + 42
b) EF = DI - GH
= 2x + 3 - x
= 2x - x + 3
= x + 3
c) FG = HI - ED
= 12 + 2x - (x + 5)
= 12 + 2x - x - 5 {To open the brackets, (-1) is distributed to x and 5}
= 12 - 5 + 2x - x
= 7 + x
d) Perimeter of DEFGHI = DE + EF + FG + GH + HI + ID
= x + 5 + x + 3 + 7 +x + x + 12 +2x + 2x + 3
= x +x + x + x + 2x + 2x + 5 + 3 + 7 + 3 + 12
= 8x + 30
Beck add like terms so you get
4x^2 -4x-15
lucy factor our negative so you left with -4x^2 +5x -10 +8x^2 -9x -5
simplify 4x^2 -4x -15
therefore both students answers simplify to 4x^2 -4x -15
Answer:
- all right angles are congruent.
- opposite sides of a parallelogram are congruent
- SAS congruence postulate
- corresponding parts of congruent triangles are congruent
Step-by-step explanation:
Given : Parallelogram JKLM is a rectangle and by the definition of rectangle,
are right angles,
Since all interior angles of rectangle are right angle.
then
, because all right angles are congruent.
Also, opposite sides of a parallelogram are congruent.
and
by the reflexive property of congruence.
Now, by the SAS congruence postulate,
,
Since corresponding parts of congruent triangles are congruent, ∴

- The SAS postulate says that if two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle then the two triangles are congruent.
It must go through both the first and last points.