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ryzh [129]
3 years ago
13

William is reading a book for class. The book is 94 pages long. For the first assignment, William read 25 pages. For the second

assignment, he read 37 pages. For the last assignment, he has to finish the book. How many pages does he have left to read?
Mathematics
2 answers:
Digiron [165]3 years ago
6 0

Answer:

32

Step-by-step explanation:

94-25-37=

Zolol [24]3 years ago
4 0

Answer:

Step-by-step explain. You first add the first 25 pages and the next 37 pages and delete that number for the total of pages that needs to be read

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Answer:

\large\boxed{\dfrac{dy}{dx}=2\sin(3x)+6\cos(3x)}

Step-by-step explanation:

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6 0
3 years ago
Help please and thank you
aksik [14]
Remember
(a^b)^c=a^{bc}
and
\frac{x^a}{x^b}=x^{a-b}


so

\frac{(7^2)^5}{7^{-6}}=
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\frac{7^{10}}{7^{-6}}=
7^{10-(-6)}=
7^{10+6}=
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the answer is D
5 0
3 years ago
To assess the precision of a laboratory scale, we measure a block known to have a mass of 1 gram. we measure the block n times a
vlada-n [284]
<span>n = 5 The formula for the confidence interval (CI) is CI = m ± z*d/sqrt(n) where CI = confidence interval m = mean z = z value in standard normal table for desired confidence n = number of samples Since we want a 95% confidence interval, we need to divide that in half to get 95/2 = 47.5 Looking up 0.475 in a standard normal table gives us a z value of 1.96 Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula 0.0001 = z*d/sqrt(n) Substitute the value z that we looked up, and get 0.0001 = 1.96*d/sqrt(n) Substitute the standard deviation that we were given and 0.0001 = 1.96*0.001/sqrt(n) 0.0001 = 0.00196/sqrt(n) Solve for n 0.0001*sqrt(n) = 0.00196 sqrt(n) = 19.6 n = 4.427188724 Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>
8 0
2 years ago
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grandymaker [24]
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5 0
3 years ago
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A yacht that travels 1.375 km in 165 minutes expressed in km/h
Tomtit [17]

The speed of a yacht traveling a distance of 1.357 km in 165 minutes is 0.5 km/h

<h3>What is Speed?</h3>

The speed of an object is the distance covered by the object in respect to time.

Mathematically:

\mathbf{Speed = \dfrac{distance}{time}}

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  • We know that 60 minutes = 1 hour
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\mathbf{Speed = \dfrac{1.375 \ km}{2.75 \ hours}}

Speed = 0.5 km/hour

Learn more about calculating speed here:

brainly.com/question/4931057

8 0
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