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ryzh [129]
3 years ago
13

William is reading a book for class. The book is 94 pages long. For the first assignment, William read 25 pages. For the second

assignment, he read 37 pages. For the last assignment, he has to finish the book. How many pages does he have left to read?
Mathematics
2 answers:
Digiron [165]3 years ago
6 0

Answer:

32

Step-by-step explanation:

94-25-37=

Zolol [24]3 years ago
4 0

Answer:

Step-by-step explain. You first add the first 25 pages and the next 37 pages and delete that number for the total of pages that needs to be read

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I need answers for A -F
mestny [16]

Answer:

A. 103º

B. 96º

C. m<4 = m<10

D. m<1 = m<16

E. m<5 = m<13

F. m<14 + m<15 = 180º

(Not entirely sure for C-F... But I hope this helps!)

8 0
3 years ago
PLESE HELP UREGNET GEOMTERY
Dima020 [189]

D is the distance from moon to sun, and it's the hypotenuse of a right triangle.


Y is opposit to angle X


Sin (x) = y/d =


D = Y/sin(x)

3 0
3 years ago
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

viscous force = 2 N

speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

Formulating initial value problem

y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m

f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

3 0
4 years ago
Help me with this please!
DedPeter [7]

Answer:

Area of triangle = 20√2

Step-by-step explanation:

Formula:

Area of triangle = bh/2

b - base  of triangle

h - height of triangle

<u>Distance formula</u>

d = √(x₂ - x₁)² +(y₂ - y₁)²

From the figure we can see that, the given triangle is right angled triangle.

Base = AC and Height = AB

<u>To find AB and AC</u>

A(1,3), B(4,7) and C(9, -5)

AB =  √(4 - 1)² +(7 - 3)² =  √(3² + 4²) = 5

AC = √(9 - 1)² +(-5 - 3)² =  √(8² + -8²) = 8√2

<u>To find the are of triangle</u>

Area = bh/2 = (5* 8√2)/2 = 20√2

Therefore the area of triangle = 20√2 square units

8 0
4 years ago
Read 2 more answers
What is the sum of natural numbers less than 200 neither divisible by 3 nor by 5
Sveta_85 [38]

Step-by-step explanation:

The required sum 

=(1+2+3+...+199)−(3+6+9+...+198)−(5+10+15+...+195)+(15+30+45+...+195)

=2199(1+199)−266(3+198)−239(5+195)+213(15+195)

 

=199×100−33×201−39×100+13×105=10732

8 0
3 years ago
Read 2 more answers
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