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ryzh [129]
4 years ago
13

William is reading a book for class. The book is 94 pages long. For the first assignment, William read 25 pages. For the second

assignment, he read 37 pages. For the last assignment, he has to finish the book. How many pages does he have left to read?
Mathematics
2 answers:
Digiron [165]4 years ago
6 0

Answer:

32

Step-by-step explanation:

94-25-37=

Zolol [24]4 years ago
4 0

Answer:

Step-by-step explain. You first add the first 25 pages and the next 37 pages and delete that number for the total of pages that needs to be read

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Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F’G’H’I’
frez [133]

Answer:

The answer is "\bold{(x,y)\longrightarrow (x-8, y-7)}".

Step-by-step explanation:

In the given question some data is missing. so, the correct answer to this can be explained in the following example:

In the given example, point D  is also known as the coordinates in the (2, 5), and in the coordination of the D prime (D') and after translation its co-ordinates value is (-6, -2). Since the very first choice is only accurate as:

⇒2-8 = -6

⇒ 5-7 = -2

It can try certain things too and see why this alone is the correct translation.  

7 0
3 years ago
Simplify the expression. 6(7n – 5m) + 8m
balandron [24]
6 (7 n - 5 m) + 8 m
6 (7 n - 5 m) = 42 n - 30 m:
42 n - 30 m + 8 m
Grouping like terms, -30 m + 42 n + 8 m = 42 n + (8 m - 30 m):
42 n + (8 m - 30 m)
8 m - 30 m = -22 m:
42 n + -22 m
Factor 2 out of 42 n - 22 m:
Answer: 2 (21 n - 11 m)
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3 years ago
Let c be the path c(t) = (2t, t2, log(t)), defined for t > 0. find the arc length of c between the points (2, 1, 0) and (12,
V125BC [204]
The path starts at t=1 and ends at t=6, so we have an arc length of


\displaystyle\int_{\mathcal C}\mathrm dS=\int_{t=1}^{t=6}\|\mathbf c'(t)\|\,\mathrm dt
=\displaystyle\int_1^6\sqrt{2^2+(2t)^2+\left(\frac1t\right)^2}\,\mathrm dt
=\displaystyle\int_1^6\sqrt{4t^2+4+\frac1{t^2}}\,\mathrm dt
=\displaystyle\int_1^6\frac1t\sqrt{4t^4+4t^2+1}\,\mathrm dt
=\displaystyle\int_1^6\frac1t\sqrt{(2t^2+1)^2}\,\mathrm dt
=\displaystyle\int_1^6\frac{2t^2+1}t\,\mathrm dt
=\displaystyle\int_1^6\left(2t+\frac1t\right)\,\mathrm dt
=t^2+\log t\bigg|_{t=1}^{t=6}
=(6^2+\log6)-(1^2+\log1)=35+\log6
4 0
4 years ago
What is the percent of change from 8 to 2
lorasvet [3.4K]

Answer:

400% is the answer.....

6 0
3 years ago
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The element silicon has a molar mass of 28.09 g/mol. Calculate the mass of 0.15 mol of Silicon.
Sav [38]

The answer is 28.09 g. I hope this helped.

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