William is reading a book for class. The book is 94 pages long. For the first assignment, William read 25 pages. For the second
2 answers:
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Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.
b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
Answer:
OR 77.78%
Step-by-step explanation:
So, we first need to find out how many numbers fit the "less than 29 or odd" group.
This would be: 1, 2, 3, 5, 15, 21, and 29, which is a total of 7 numbers.
Next, we figure out the total amount of numbers in the population.
This would be: 1, 2, 3, 5, 15, 21, 29, 38, and 500, which is a total of 9 numbers.
Finally, we put the first number (7) over the total (9) =
is now able to be written in a percentage, if you need.
The probability is OR 77.78%