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OLEGan [10]
3 years ago
15

The chart below shows the resting heart rate of members of a fitness class

Mathematics
1 answer:
Nataly_w [17]3 years ago
6 0

wheres the chart? lol

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Please & thankssssss
malfutka [58]
Multiply both sides of the equation by 28 4y+7=10
Then move constants to the right side and change its sign 4y=10-7
Now subtract the numbers 4y=3 divide both sides by 4 so your answer is y=3/4
8 0
2 years ago
What type of jobs offer commissions?
Vedmedyk [2.9K]

Answer:

Sales Engineers. ...

Wholesale and Manufacturing Sales Representatives. ...

Securities, Commodities, and Financial Services Sales Agents. ...

Advertising Sales Agent. ...

Insurance Sales Agent. ...

Real Estate Brokers and Sales Agents. ...

Travel Agents.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A car leaves at 9 : 00 a.m. and drives at a constant speed. It is 20 miles from its starting point at 9 : 30 a.m. At what time w
Ilya [14]

Answer:

2:00 PM

Step-by-step explanation:

I figured out that the car is going 40 mph seeing as how it went 20 miles in 30 minutes.

I used this and found out how many hours it would take to get to 200 miles at this rate:

200/40 = 5

I divided 40 by 200 as 200 is the end goal and the car is going 40 mph.

The 5 is 5 hours, so I added 9 and 5 to get 14 which is 2:00 PM

Hope this helps!! :)

6 0
2 years ago
Please help I will give brainly
Aleks04 [339]

ok so the easy way is this

Marc says he will have 20 if he doubles his cards.

if u divide 20 by 2 = 10

but His friend gave him 3 cards before.which means that

10-3 = 7

He started with 7 cards

I answered b and c.

5 0
3 years ago
Read 2 more answers
Please help. . . . . . . . .
wlad13 [49]

9514 1404 393

Answer:

  recursive: 5, 3, 2

  explicit: 5, 3

Step-by-step explanation:

First of all, you can identify the first term as a1 = 5.

Then you can see that the ratio of consecutive terms is ...

  15/5 = 45/15 = 135/45 = 405/135 = 3 . . . the common ratio

In the recursive formula, a1 is the first term (5), and the multiplier getting you to the next term is the common ratio (3). The recursion relation is good for values of n such that n-1 is at least 1. That is, n ≥ 2.

  \text{The recursive rule is }a_1=\boxed{5}\text{ and }a_n=\boxed{3}a_{n-1}\text{ for }n\ge\boxed{2}

__

The explicit rule is formed the way the problem statement tells you: the first term times a power of the common ratio.

  \text{The explicit rule is }a_n=\boxed{5}(\boxed{3})^{n-1}

5 0
2 years ago
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