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kramer
3 years ago
8

MINING A mine produces 42.5 tons of coal per hour. How much coal will the mine produce in 9.5 hours?

Mathematics
2 answers:
vladimir1956 [14]3 years ago
7 0

Given

MINING A mine produces 42.5 tons of coal per hour.

Find out the how much coal will the mine produce in 9.5 hours.

To proof

As given in the question

A mine produces 42.5 tons of coal per hour i.e in the 1 hour mine produces the 42.5 tons .

Let us assume that the coal produce in the 9.5 hours be x.

than the equation becomes

x = 9.5 × 42.5

x =  403 . 75 tons

 403 . 75 tons coal will the mine produces in the 9.5 hours.

Hence proved








lisabon 2012 [21]3 years ago
7 0

Answer:

403.75 tons of coal.

Step-by-step explanation:

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Answer:

a)Slope: \hat \beta_1 =\frac{7625.9}{1248.9}=6.106

Intercept: \hat \beta_o = 157.955 -6.106 (69.686)=-267.548

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n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9 , sum y^2_i=\sum(y-\bar y)^2 =94228.8  

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Part a

The slope is given by this formula:

\hat \beta_1 =\frac{\sum (x-\bar x) (y-\bar y)}{\sum (x-\bar x )^2}

If we replace we got:

\hat \beta_1 =\frac{7625.9}{1248.9}=6.106

We can find the intercept with the following formula

\hat \beta_o = \bar y -\hat \beta_1 \bar x

We can find the average for x and y like this:

\bar X=7665.5/110 =69.686, \bar y= 17375/110=157.955

And replacing we got:

\hat \beta_o = 157.955 -6.106 (69.686)=-267.548

Part b

In order to calculate the correlation coefficient we can use this formula:  

r=\frac{\sum (x-\bar x)(y-\bar y) }{\sqrt{[\sum (x-\bar x)^2][\sum(y-\bar y)^2]}}  

For our case we have this:  

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9 , sum y^2_i=\sum(y-\bar y)^2 =94228.8  

So we can find the correlation coefficient replacing like this:

r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657  

And the determination coeffecient is r^2 = 0.657^2 =0.432  

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