A line segment has endpoints (-5, 10) and (a,b) . If the midpoint of the segment is (13, -2), what is the absolute difference be

Question

anygoal [31]

3 years ago

7

A line segment has endpoints (-5, 10) and (a,b) . If the midpoint of the segment is (13, -2), what is the absolute difference be

tween a and b ?

Mathematics

1 answer:

AlexFokin [52] · Answer 1 · 2022-08-27T17:17:45+03:00

If the line segment point is D(-5, 10) and E(a,b) and the midpoint of the segment is F(13, -2) that mean
DE= 2*DF

You can directly find the distance of AC
Xdf= Xf-Xd= 13 - (-5)= 18
Ydf= Yf - Yd= -2 - 10= -12

Then add the distance of AB( which is 2*AC) to point D
Xe= a = Xd + 2*Xdf
a= -5 +2*18= 31

Ye= b = Yd + 2Yf
b= 10+ 2*-12= -14

<span>absolute difference between a and b:
|b-a|= </span>|-14-31|= 45