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tresset_1 [31]
3 years ago
10

0.17k - 0.43 = 0.25k + 0.05

Mathematics
1 answer:
Volgvan3 years ago
4 0

Answer:

-6

Step-by-step explanation:

0.17k - 0.43 =0.25k + 0.05

Collect like terms

0.17k - 0.25k =0.43 + 0.05

-0.08k = 0.48

Divide both sides by -0.08

K = 0.48/-0.08

K = -6

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Simplify the radical expression. Please explain how you got your answer. <br><br> √25*√4
Deffense [45]
Since both numbers are in the radical just multiply and get sq rt

25 times 4 =100
√100=10 answer
6 0
4 years ago
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Employment data at a large company reveal that 74% of the workers are married, 42% are college graduates, and that 56% are marri
ValentinkaMS [17]

Answer:

(E) None of these above are true.

Step-by-step explanation:

Married = 74% or 0.74

College graduates = 42% or 0.42

pr(married | college graduates) = 0.56

(A) These events are pairwise disjoint. This is false. Pairwise disjoint are also known as mutually exclusive events. Here we can see that both events are occurring at same time.

(B) These events are independent events. This is also false.

(C) These events are both independent and pairwise disjoint. False

(D) A worker is either married or a college graduate always. False

Here Probability(A or B) shall be 1

= Pr(A) + Pr(B) - Pr( A and B) = 0.74 + 0.42 - 0.56 * 0.42 = 0.9248

This is not equal to 1.

(E) None of these above are true. This is true.

8 0
4 years ago
A computer programming team has 17 members. (a) How many ways can a group of nine be chosen to work on a project? As in Example
Natali5045456 [20]

The number of groups that can be chosen from the team of 17 depends on the given conditions of the selection.

The correct responses are;

(a) The number of ways of choosing groups of 9 from the 17 members are 24,310 ways.

(b) (i) The number of groups of 9 containing 5 women and 4 men are 8,820 groups.

(ii) The number of groups of 9 that contain at least one man is 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) If two team members refuse to work together on projects, the number of groups of 9 that can be chosen are 17,875 groups.

(d) If two team members must work together or not at all the number of groups of 9 that can be chosen are 1,430 groups.

Given,

The combination of n objects taking r at a time is given as follows

ₙCr = (ⁿr)

(a) The number of ways of choosing groups of 9 from the 17 members is given as follows;

Number of ways of choosing groups of 9 = (17, 9)  = 24,310 ways.

(b) (i) Number of women = 9

Number of men = 8

Number of groups of 9 containing 5 women and 4 men = (9, 5) x (8, 4)

(9, 5) x (8, 4) = 126 x 70 = 8820

Number of groups of 9 containing 5 women and 4 men = 8,820 groups.

(ii) The number of groups that contain at least one man is (17, 9) - (9, 9)

(17, 9) - (9, 9) = 24,310 - 1 = 24,309

The number of groups that contain at least one man are 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women if given as follows;

(8, 8) × (9, 1) + (8, 7) × (9, 2) + (8, 6) × (9, 3) = 2649

The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) Given that two team members refuse to work together on projects, the number of groups of 9 that can be chosen are (15, 9) + 2 × (15, 8)

(15, 9) + 2 × (15, 8) = 5,005 + 2 × 6,435 = 17,875

(d) Two team members must work together or not at all is (15, 7) - (15, 9)

(15, 7) - (15, 9) = 6,435 - 5,005 = 1,430

The number of groups of 9 that can be chosen two team members must work together or not at all are 1,430 groups.

Learn more about number of ways here;

brainly.com/question/25310371

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7 0
1 year ago
Find the sum and express it in simplest form (6u-7c-6)+(-2u+4c)
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4u+3c-6 is thats what its asking for? just puting the same variables together
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3 years ago
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Plz help I don’t know the answer
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Are there options for the answers or not? If there is add the options.
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