<h3>Answer:</h3>
6 moles of H₂O / 9 moles of O₂
<h3>Explanation:</h3>
The Balance Chemical Equation is as follow,
2 C₃H₆ + 9 O₂ → 6 CO₂ + 6 H₂O
According to this balance equation 2 moles of C₃H₆ (Propene) when combusted with 9 moles of O₂ (Oxygen) produces 6 moles of CO₂ (Carbon Dioxide) and 6 moles of H₂O (Water Vapors).
Hence, Given options are;
1 mole of C₃H₆ / 2 moles of CO₂: This is incorrect because 1 mole of C₃H₆ will produce 2 moles of CO₂.
6 moles of H₂O / 9 moles of O₂: This is correct as 6 moles of H₂O is produced by reacting 9 moles of O₂.
2 moles of C₃H₆ / 6 moles of O₂: This ratio is incorrect because for complete oxidation 2 moles of C₃H₆ requires 9 moles of O₂.
3 moles of H₂O / 2 moles of CO₂: This is also incorrect because the production of 3 moles of H₂O will be accompanied by the production of 3 moles of CO₂.