<h3>x²+5x+3+2x²+10x15 =0</h3><h3>x²+2x²+5x+10x+3+15=0</h3><h3>3x²+15x+18=0</h3><h3>3(x²+5x+6) =0 because 3 is common factor</h3><h3>3(x²+3x+2x+6) spill the middle term</h3><h3>3(x(x+3)+2(x+3) take the common factor from term</h3><h3>3(x+2) (x+3)</h3>
<h3>answer is 3(x+2) (x+3)</h3>
please mark this answer as brainlist
For these models there are methods such as the perturbation method which can<span> be used to find an approximate analytical solution within a certain range. The </span>advantage<span> here over a </span>numerical<span> solution is that </span>you<span> end up with an equation (</span><span>instead of just a long list of numbers) which </span>you can<span> gain some insight from.</span>
Answer: 153
Step-by-step explanation:
When we have a group of N elements, the total number of combinations of K elements ( K ≤ N) is:
Where N! = N*(N - 1)*(N - 2)*...*2*1
In this case, we have a group of 18 people (then N = 18) and we want to see how many different combinations of 2 we can make (K = 2).
Using the above equation we get:
There are 153 different ways in which the manager can do this.
Answer: 2 + 6x
Step-by-step explanation:
i cannot do the graph here but you just have to put the amount deposited in this instance as the variable and you got your answer
