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Anuta_ua [19.1K]
3 years ago
8

if a fraction can be written as a repeating decimal, only on digit can repeat over over without end. true or false

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

False

Step-by-step explanation:

I will prove that it's false by giving some examples:)

  • 1/11 = .09090909... this repeats two digits, not just one!
  • 1/81 = .01234567... this repeats every digit from 0 to 9! If that isn't cool, I don't know what is.
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Does this graph represent a function?Why or why not?
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No, it does not have a straight line. (A)


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Need help with this ignore what a put in the box it isn’t right
Zarrin [17]

f=6cm\\g=8cm

Why?

The first thing we need to do is find the area of the triangle, we can to that by subtracting the area of ABCD from ACBE, then, we can use the formulas to calculate the area for both triangle and rectangle to find "f" and "g".

Calculating we have:

TriangleArea=ABCE-ABCD\\\\TriangleArea=60cm^{2}-48cm^{2}=12cm^{2}

Now, we can calculate "f" by using the formula to calculate the area of the triangle:

TriangleArea=\frac{b*h}{2}\\\\TriangleArea=\frac{f*4cm}{2}\\\\12cm^{2}*2=f*4cm\\\\\frac{24cm^{2}}{4cm}=f\\\\f=6cm

Now, finding "g" by using the formula to calculate the area of the rectangle, we have:

RectangleArea=ABCD\\\\ABCD=Base*Height\\\\48cm^{2}=base*6cm\\\\base=g=\frac{48cm^{2}}{6cm}=8cm

Hence, we have that:

f=6cm\\g=8cm

Have a nice day!

8 0
3 years ago
Use vectors to find the interior angles of the triangle with the given vertices. (Enter your answers as a comma-separated list.
aleksandr82 [10.1K]

Answer:

  23.20°, 71.57°, 85.24°

Step-by-step explanation:

The angle between two vectors can be found by making use of the definition of the dot product. The computed angle is the angle between the  vectors when they are placed tail-to-tail.

__

<h3>setup</h3>

<u>vector definition</u>

The second attachment shows the given points plotted as A, B, C in the order given. In the diagram, the vectors <em>a</em>, <em>b</em>, <em>c</em> are defined as BA, CB, AC, respectively. That is, the vector <em>a</em> is ...

  <em>a</em> = A -B = (-6, -9) -(2, 7) = (-6-2, -9-7) = (-8, -16)

The vectors are defined in counterclockwise order around the triangle, though that makes no difference to the calculation.

<u>dot product definition</u>

The definition of the dot product of vectors A and B is ...

  A·B = |A|×|B|×cos(θ) . . . . . where θ is the angle between the vectors

Solving for the angle, we find it to be ...

  \theta=\arccos\left(\dfrac{\vec{A}\cdot\vec{B}}{|\vec{A}|\,|\vec{B}|}\right)

__

<h3>computation</h3>

Because of the way the vectors in this solution are defined, the angle between any given pair of vectors will be an <em>exterior</em> angle of the triangle. In order to find the measure of the <em>interior</em> angle, we must reverse one of the vectors. That is, the dot product used in our computation will be the <em>opposite of the dot product</em> of the vectors we have found.

The spreadsheet shown in the first attachment does the necessary computations.

  • Each vector is the difference of successive points. (x1 -x2, y1 -y2)
  • Each dot product shown is the opposite of the dot product of successive vectors. -(x1x2 +y1y2)
  • The magnitude is computed in the usual way: the root of the sum of the squares of the components of the vector. √(x²+y²)
  • The cosine is the dot product of successive vectors, divided by each of the vector magnitudes.
  • The spreadsheet shows the angle in degrees, having converted it from the radian value produced by the ACOS function.

As a check, the spreadsheet shows the sum of the angle values. (The rounded values add up to 180.01°.)

The interior angles of the triangle are 23.20°, 71.57°, 85.24°.

_____

<em>Additional comment</em>

Another way to find the interior angles from coordinates is to consider the slope of each side of the triangle as being the tangent of the angle it makes with the x-axis. The difference of these angles can be used to find the interior angles of the triangle. Less work is involved because there is no dot-product or magnitude computation.

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In which quadrant is sec e&lt; 0 and tan e &gt; 0?
iren2701 [21]

Answer:

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Step-by-step explanation:

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