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3 years ago

What’s the difference between the polynomials ?

Mathematics

1 answer:

babymother [125]3 years ago

4 0

Answer:

7x^2-4x+3y^2 ( the ^ means the exponent EX: 5^2 is 5 squared. )

Step-by-step explanation:

Remove the parenthesis (a) = a

12x^2-11y^2-13x- (5x^2-14y^2-9x)

-(5x^2 - 14y^2 - 9x)

Distribute parenthesis

-(5x^2) - (14y^2) - (-9x)

Apply minus - plus rules

-5x^2 + 14y^2 + 9x

= 12x^2 - 11y^2 - 13x - 5x^2 + 14y^2 + 9x

Simplify

12x^2-11y^2-13x-5x^2+14y^2+9x

Group like terms

12x^2-5x^2-13x+9x-11y^2+14y^2

Add similar elements

7x^2-13x+9x-11y^2+14y^2

Add similar elements ( - 13x + 9x = -4x )

7x^2-4x-11y^2+14y^2

Add similar elements 11y^2 + 14y^2 = 3y^2

7x^2-4x+3y^2

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4 years ago

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3 years ago

In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t

Angelina_Jolie [31]

Answer:

$P(X = 0) = 0.027$

$P(X = 1) = 0.189$

$P(X = 2) = 0.441$

$P(X = 3)= 0.343$

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each $x \leq n$ , the probability mass function is given by:

$P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}$

In which p is the probability that the event happens.

$pe_{n,x},$ is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

$pe_{n,x} = \frac{n!}{x!}$

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so $n = 3$

The probability that a wafer pass a test is 0.7, so $p = 0.7$

Determine the probability mass function of the number of wafers from a lot that pass the test.

$P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027$

$P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189$

$P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441$

$P(X = 3) = (0.7)^{3} = 0.343$

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4 years ago