Mass box A = 10 grams; Mass box B = 5 grams; Mass box C-made of one A and one B
1 answer:
Answer:
2 boxes
Explanation:
==>Given that:
Box A = 10 grams
Box B = 5 grams
Box C= 1 A and 1 B = 15 grams
==>Required:
Number of boxes of B that would make 30 grams of C
==>Solution:
We know that, 1 box of B would give us 15grams of of C when mixed in the right proportion with 1 box of A.
thus,
1 box of B => 15 grams of C
x box of B => 30 grams of C
Therefore x = (30*1)/15
x = 30/15
x = 2
2 boxes of B would be required to make 30 grams of C
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