16.94/18=.9411111
sig figs: 0.9411 mole of water
Cesium is the element in group 1A that has the largest atomic radius, with the number of 225.
Rubidium has 211, Potassium 196, and Sodium 154.
Answer:
K.E = 19125 j
Explanation:
Given data:
Mass = 150 Kg
Speed of car = 15 m/s
K.E = ?
Solution:
Formula:
K.E = 1/2 (mv²)
K.E = Kinetic energy
m = given mass
V = speed
now we will put the values in formula.
K.E = 1/2 (mv²)
K.E = 1/2 (150 Kg) (15²)
K.E = 1/2 150 Kg × 225 m²/s²
K.E = 0.5 × 225 m²/s² ×150 Kg
K.E = 19125 j
Answer:
Cl^- <S^2-<Sc^3+ <Ca^2+<K^+
Explanation:
We know that ionic radius of ions decreases from right to left in the periodic table. This is because, ionic radii decreases with increase in nuclear charge. This explains why; Sc^3+ <Ca^2+<K^+.
Secondly, even though Cl^- is isoelectronic with S^2-, the size of the nuclear charge in Cl^- is larger compared to that of S^2- . Hence Cl^- is smaller than S^2- in ionic radius owing to increased nuclear attraction in Cl^-.
Answer:
Number 3.
Explanation: The sun produces radiation in the car, which then becomes hot because much radiation is coming in, but little goes out.
