(y+3)(y^2-3y+9)
=y(y^2-3y+9)
+3(y^2-3y+9)
=(y^3-3y^2+9y)+(3y^2-9y+27)
=y^3-3y^2+9y+3y^2-9y+27
=y^3+27
5 because increased by means to add 2+3
and quotient means the answer to a division problem 10/2 so ur answer is 5
Answer:
1/4 is the common ratio for the geometric sequence
Answer:
Convergent; 81
Step-by-step explanation:
r = term2/term1 = 8/9
8/9 < 1 so convergent
Sum = 9/(1 - 8/9)
= 9/(1/9) = 81
Answer:
y = 4/5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
7/8y + 1/2 = 1 1/5
<u>Step 2: Solve for </u><em><u>y</u></em>
- Convert to improper fraction: 7/8y + 1/2 = 6/5
- [Subtraction Property of Equality] Subtract 1/2 on both sides: 7/8y = 7/10
- [Division Property of Equality] Divide 7/8 on both sides: y = 4/5