Answer:
The slope of the equation y-3=-4(x-5) is -4.
Step-by-step explanation:
This equation is written in point-slope form: y-y₁=m(x-x₁), where "m" is the slope or the equations. In the equation y-3=-4(x-5), the -4 stands in the "m", or slope, spot, so the sope of this equation is -4.
Each ticket costs $19.50
You are trying to buy 125
Multiply both together
125 x 19.50 = 2437.50
$2437.50 is the total cost
hope this helps
Answer:
and
respectively.
Step-by-step explanation:
The given trigonometric equation is
We divide both sides by 
to get,
This implies that,
We take the inverse tangent of both sides to get,
Since the tangent ratio has a period of 
, another solution is
to the nearest degree.
In the third quadrant,
The solutions are
The value of x that satisfies the equation if x lies in the second quadrant is
The value of x that satisfies the equation if x lies in the third quadrant is
Answer:
∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° , ∠KLJ = 86°
Step-by-step explanation:
Here, given In ΔJLK and ΔMLP
Here, JK II ML, LM = MP
∠JLM = 22° and ∠LMP = 36°
Now, As angles opposite to equal sides are equal.
⇒ ∠MLP = ∠MPL = x°
Now, in ΔMLP
By <u>ANGLE SUM PROPERTY</u>: ∠MLP + ∠MPL + ∠LMP = 180°
⇒ x° + x° + 36° = 180°
⇒ 2 x = 180 - 36 = 144
or, x = 72°
⇒ ∠MLP = ∠MPL = 72°
Now,as JK II ML
⇒ ∠LJK = ∠JLM = 22° ( Alternate pair of angles)
Now, by the measure of straight angle:
∠MLP + ∠JLM + ∠JLK = 180° ( Straight angle)
⇒ 72° + 22° + ∠JLK = 180°
or, ∠JLK = 86°
In , in ΔJLK
By <u>ANGLE SUM PROPERTY</u>: ∠JKL + ∠JLK + ∠LJK = 180°
⇒ ∠JKL + 86° + 22° = 180°
⇒ ∠JKL = 180 - 108 = 72 , or ∠JKL = 72°
Hence, from above proof , ∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° ,
∠KLJ = 86°
