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Vera_Pavlovna [14]

3 years ago

13

the standard form of linear equation is Ax + By = C. if b=0 and a and C are positive, which best describes the graph of this equ

ation

2 answers:

Elodia [21]3 years ago

8 0

Answer:

It is a vertical line

Step-by-step explanation:

the equation will be in the form of Ax=C hence we can make X the subject of the formula giving

$x = \frac{ a}{c}$

KatRina [158]3 years ago

8 0

It is a vertical line.

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Is x=2 a solution to the equation below? <br> 4(x-1)-3(x-2)=-8

Sonbull [250]

Answer:

No

Step-by-step explanation:

To find out if 2 is a solution, replace all the x's with 2.

4(2 - 1) - 3(2 - 2) =8

4(1) - 3(0) = 8

4 - 0 = 8

4 = 8

Nope! False! 2 is not a solution.

7 0

3 years ago

Find the measure of angle m

poizon [28]

Sum of degrees of a triangle = 180
Let’s call the missing angle x

60 + 84 + x = 180

144 + x = 180

X= 36

Hope this helps!
Brainliest is much appreciated!

3 0

3 years ago

Find the surface area of the triangular prism?.... and 31 is not the answer

irga5000 [103]

Answer:

216 sq m

Step-by-step explanation:

Surface area of triangular prism = bh + (s1 + s2 + s3)*L

Where,

b = 6 m

h = 8 m

s1 = 10 m

s2 = 8 m

s3 = 6 m

L = 7 m

Plug in the values

Surface area = 6*8 + (10 + 8 + 6)*7

Surface Area = 48 + 24*7 = 216 m²

4 0

3 years ago

Two vertical poles of heights 60 ft and 80 ft stand on level ground, with their bases 100 ft apart. A cable that is stretched fr

Andreyy89

Answer:

Step-by-step explanation:

Given

height of two Poles are 60 and 80 ft

Distance between them is 100 ft

Let x be the distance of Pole of ht 80 ft from Point of stretch

thus length of rope is given by

$L=L_1+L_2$

$L_1=\sqrt{80^2+x^2}$

$L_2=\sqrt{60^2+(100-x)^2}$

$L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}$

differentiate w.r.t x we get

$\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

Put $\frac{\mathrm{d} L}{\mathrm{d} x}=0$ to get minimum value

$\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

squaring

$x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)$

Rearranging

$28x^2-1800x+640000=0$

$x=\frac{400}{7}$

thus $L_1=98.312 ft$

$L_2=73.73 ft$

$L=172.04 ft$

7 0

3 years ago

10 > c + 5 what does c =

Fittoniya [83]

Answer:

c=1

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers