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anastassius [24]
3 years ago
7

A woman with mass 50 kg is standing on the rim of a large disk that is rotating at 0.80 rev/s about an axis through its center.

The disk has mass 270 kg and radius 4.0 m.
Calculate the magnitude of the total angular momentum of the woman–disk system. (Assume that you can treat the woman as a point.)

Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

angular momentum, L=1.4\times 10^4\ kg-m^2/s

Explanation:

Given that,

Mass of the woman, m = 50 kg

Angular velocity of the disk, \omega=0.8\ rev/s=5.02\ rad/s

Mass of the disk, m' = 2670 kg

Radius of the disk, R = 4 m

We need to find the magnitude of the total angular momentum of the woman–disk system. The moment of inertia of the system is equal to the sum of moment of inertia of women and the moment off inertia of the disk.

I=mR^2+\dfrac{1}{2}m'R^2\\\\I=R^2(m+\dfrac{1}{2}m')\\\\I=(4)^2\times (50+\dfrac{1}{2}\times 270)\\\\I=2960\ kg-m^2

The angular momentum is given by :

L=I\omega\\\\L=2960\times 5.02\\\\L=14859.2\ kg-m^2/s

or

L=1.4\times 10^4\ kg-m^2/s

So, the magnitude of the total angular momentum of the woman–disk system is 1.4\times 10^4\ kg-m^2/s. Hence, this is the required solution.

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A uniform solid sphere has mass m= 7 kg and radius r= 0. 4 m. What is its moment of inertia about an axis tangent to its surface
lilavasa [31]

The moment of inertia of a uniform solid sphere is equal to 0.448 kgm^2.

<u>Given the following data:</u>

Mass of sphere = 7 kg.

Radius of sphere = 0.4 meter.

<h3>How to calculate moment of inertia.</h3>

Mathematically, the moment of inertia of a solid sphere is given by this formula:

I=\frac{2}{5} mr^2

<u>Where:</u>

  • I is the moment of inertia.
  • m is the mass.
  • r is the radius.

Substituting the given parameters into the formula, we have;

I=\frac{2}{5} \times 7 \times 0.4^2\\\\I=2.8 \times 0.16

I = 0.448 kgm^2.

Read more on inertia here: brainly.com/question/3406242

4 0
2 years ago
An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?
seraphim [82]
Volume=mass/density

volume=455.6/19.3

volume=23.6 mL

4 0
3 years ago
Squids and octopuses propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracti
liq [111]

Answer:

The speed of water must be expelled at 6.06 m/s

Explanation:

Neglecting any drag effects of the surrounding water we can assume the linear momentum in this case is conserves, that is, the total initial momentum of the octopus and the water kept in it cavity should be equal to the total final linear momentum. That's known as conservation of momentum, mathematically expressed as:

p_f=p_i

with Pi the total initial momentum and Pf the final total momentum. The total momentum is the sum of the momentums of the individual objects, in our case the octopus and the mass of water that will be expelled:

p_{of}+p_{wf}=p_{oi}+p_{wi}

with Po the momentum of the octopus and Pw the momentum of expelled water. Linear momentum is defined as mass times velocity:

m_o*v_{of}+m_w*v_{wf}=m_o*v_{oi}+m_w*v_{wi}

Note that initially the octopus has the water in its cavity and both are at rest before it sees the predator so v_{oi}=v_{wi} = 0\frac{m}{s}:

m_o*v_{of}+m_w*v_{wf}=0

We should find the final velocity of water if the final velocity of the octopus is 2.70 m/s, solving for v_{wf}:

v_{wf}=-\frac{m_o*v_{of}}{m_w}=-\frac{(6.00-1.85)*(2.70)}{1.85}

v_{wf}=-6.06\frac{m}{s}

The minus sign indicates the velocity of the water is opposite the velocity of the octopus.

3 0
3 years ago
Use the law of universal gravitation to describe the relationship between you and your desk
tangare [24]
The law of gravitation states that things closer to the core of gravitation, have a larger force pulling down on them. In relation of you to your desk, you and the desk are both drawn downwards towards the center of gravity.
6 0
3 years ago
Un avión de rescate en Alaska deja caer un paquete de provisiones a un grupo de exploradores extraviados. Si el avión viaja hori
posledela

Answer:

180.4 m

Explanation:

The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:    

$V_{ox}=v_x = 40 \ m/s$

   h = 100 m  

    x =?

     Height formula h:

     $h=g \times \frac{t^2}{2}$

      Time t is cleared:

     $t = \sqrt{\frac{2h}{g}}$

      $t = \sqrt{\frac{2 \times 100}{9.8}}$

      t = 4.51 sec

 Horizontal distance formula x:

       $x=V_x \times t$

        x = 40 m / sec x 4.51 sec

        x = 180.4 m

4 0
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