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2 years ago

n an object. one force is 3N to the east and the other force is 9n to the west. what is the net force acting on the object

Physics

1 answer:

cricket20 [7]2 years ago

4 0

Answer:

-6N

Explanation:

The force to the east is acting in the positive x-direction therefore it is positive. The force to the east is in the negative x-direction therefore it is negative. The net force is just the sum of the two so 3-9=-6

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¿que acciones o actitudes de tiempo de inmovilizacion obligatoria descubrimos o hemos fortalecido en casa con familia?

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Answer:

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3 years ago

A particle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. Its initial position

Illusion [34]

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Place of particles

$X(t)=\int V_{x}(t)dt$

$=\int 2t^{2}dt\\\\=\frac{2}{3}t^{3}+C$

$\to t=0\\\\ \to X(0)=2.3 \ m$

$\to X(0)=0+C\\\\ \to C=2.3\ m$

$\to X(t)=( \frac{2}{3})t^3 + 2.3\\\\ \to t=2.2\\\\\to X=( \frac{2}{3})\times 2.2^3 +2.3 \\\\$

$= \frac{2}{3}\times 10.648 +2.3\\\\= \frac{21.296}{3}+2.3\\\\ = 7.09+2.3\\\\ =9.39\\\\ =9.4\ m$

In point b:

when $t=2.2 \ s$

the Particle velocity $(V)=2 \times 2.22 =9.68\ \frac{m}{s}$

In point c:

Calculating the Particle acceleration:

$\to a=\frac{dV}{dt} =4\ t\\\\\to t=2.2 \ s\\\\\to a=4\times 2.2 =8.8 \ \frac{m}{s^2}$

8 0

3 years ago

A bowler throws a bowling ball of radius R = 11 cm along a lane. The ball slides on the lane with initial speed vcom,0 = 6.0 m/s

ankoles [38]

Answer:

Explanation:

Radius of the ball is $R=11cm=0.11m$

Initial speed of the ball is $v_{com0}=6.0m/s$

Initial angular speed of the ball is $\omega = 0$

Coefficient of kinetic friction between the ball and the lane

is $\mu =0.35$

Due to the presence of frictional force, ball moves with

decreasing velocity.

(a)

velocity $v_{com0}$ in terms of $\omega$ is

$V_{com0} = -R\omega\\\\=-(0.11m)\omega\\\\= (-0.11\omega)m/s$

(b)

Ball's linear acceleration is given by

$a=-\mu g\\\\=-(0.35) (9.8 m/s^2)\\\\= -3.43m/s^2$

(c)

During sliding, ball's angular acceleration is calculated as

$\alpha=-\frac{\tau}{I}\\\\-\frac{\mu mgR}{(\frac{2}{5}mR^2)}\\\\-\frac{2}{5}\frac{\mu g}{R}\\\\-\frac{2}{5}\frac{(0.35)(9.8)}{0.11}\\\\-77.95rad/s^2$

(d)

The time for which the ball slides is calculated from the

equation of motion is

$V_{cm}= V_{cm0} + at\\\\V_{cm} = V_{cm0} + (-\mu g )t\\\\-0.11\omega=6.0m/s -(3.43m/s^2 )t\\\\-(0.11) (\alpha t) =6.0 m/s - (3.43 m/s^2)\\\\- (0.11)(-77.95 rad/s^2)t = 6.0m/s - (3.43 m/s^2 )t\\\\8.5745t + 3.43t= 6.0\\\\12.0045t = 6.0\\\\t= 0.4998s$

(e)

Distance traveled by the ball is

$X= V_{com,0}+ \frac{1}{2}at^2\\\\= (6.0m/s)(0.4998 s)+ 0.5(-3.43m/s^2) (0.4998 s)^2\\\\=2.57m$

(for)

The speed of the ball when smooth rolling begins is

$V_{cm} = V_{com, 0}+ at\\\\=6.0 m/s +(-3.43m/s^2 )(0.4998 s)\\\\= 4.29m/s$

5 0

3 years ago

Read 2 more answers

Use what you know about mass and how you use it to calculate force in the following situation. If each washer has a mass of 4. 9

mina [271]

Considering the change of units and the definition of weight, the mass of two washers would be 0.0098 kg and if 4 washers are attached to the string, then the applied force on the car will be 0.196 N.

Mass of two washers

If each washer has a mass of 4.9 g, then the mass of two washers will be calculated simply by multiplying the mass of 1 washer by the amount you have of them, in this case 2:

4.9 g×2= 9.8 g

Being 1 kg = 1000 g, you apply the following rule of three to make the change of units: if 1000 g equals 1 kg, 9.8 g equals how many kilograms?

$mass=\frac{9.8 gramsx1 kg}{1000g}$

Solving:

mass= 0.0098 kg

Finally, the mass of two washers would be 0.0098 kg.

Applied force

On the other side, mass is the amount of matter that a body contains and weight is the action exerted by the force of gravity on the body.

The mass of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

Weight is calculated as the product of the object's mass and the value of the gravitational acceleration:

W= m×g

In this case, you know:

m= 4.9 g×4= 19.6 g= 0.0196 kg → the mass of 4 washers in kilograms
g= 10 m/s²

Replacing:

W= 0.0196 kg× 10 m/s²

Solving:

W= 0.196 N

Finally, if 4 washers are attached to the string, then the applied force on the car will be 0.196 N.

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3 years ago

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Which happens to the magnetic field of a wire when you change the direction of the current in the wire? The magnetic field _____

zavuch27 [327]

The direction of the magnetic field around a wire depends on
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3 years ago

n an object. one force is 3N to the east and the other force is 9n to the west. what is the net force acting on the object ​

n an object. one force is 3N to the east and the other force is 9n to the west. what is the net force acting on the object