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3 years ago

Which is the oldest of the following sports

2 answers:

7 0

Soccer was made in 19th December 1863, football was November 6, 1869 (ha), baseball was 1839, track and field is 776 BC,

Sergeeva-Olga [200]3 years ago

3 0

I'm pretty sure it's track & field! If I recall correctly, track & field was a major part of the Olympics as they were first performed in Ancient Greece.

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Describe the tide requirements necessary to create a tidal power plant.

spin [16.1K]

Answer:

La energía mareomotriz se produce gracias al movimiento generado por las mareas, esta energía es aprovechada por turbinas, las cuales a su vez mueven la mecánica de un alternador que genera energía eléctrica, finalmente este último esta conectado con una central en tierra que distribuye la energía hacia la comunidad.

6 0

3 years ago

Which statement about stage 3 NREM is accurate?

cestrela7 [59]

Answer:

hope

that helps

Explanation:

D. The sleeper's heart rate, blood pressure, and breathing rate drop to their lowest levels.

8 0

2 years ago

A thick steel sheet of area 100 in.2 is exposed to air near the ocean. After a one-year period it was found to experience a weig

vladimir1956 [14]

Answer:

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

Explanation:

The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

$CPR=\frac{KW}{DAT}$

K= constant depends on the system of units used.

W= weight =485 g

D= density =7.9 g/cm³

A = exposed specimen area =100 in² =6.452 cm²

K=534 to give CPR in mpy

K=87.6 to give CPR in mm/yr

mpy

$CPR=\frac{KW}{DAT}$

$=\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}$

=37.4mpy

mm/yr

$CPR=\frac{KW}{DAT}$

$=\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}$

=0.952 mm/yr

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

3 0

3 years ago

In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added

amid [387]

Answer:

187 J

Explanation:

First Law of Thermodynamics :

ΔQ = ΔW + ΔU

ΔQ : Heat. If it added to system then positive and if it is rejected by system then negative.

ΔW : Work. If it done by the system then positive and if it is done on system then negative.

ΔU : Internal Energy. If it positive then temperature of system increased and if it is negative then temperature of system decreased.

ΔQ = 79 J

ΔW = - 108 J

ΔU = ?

substituting the value in the equation:

79 = -108 + ΔU

∴ ΔU = 187 J

7 0

3 years ago

A physical quantity X is connected from X = ab2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3

Hoochie [10]

Answer: 11%

Explanation:

Given that

X = ab^2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3 respectively.

Percentage error of b = 2%

Percentage error of b^2 = 2 × 2 = 4

When you are calculating for percentage error that involves multiplication and division, you will always add up the percentage error values.

Percentage error of X will be;

Percentage error of a + percentage error of b^2 + percentage error of c

Substitute for all these values

4 + 4 + 3 = 11%

Therefore, percentage error of X is 11%

3 0

3 years ago