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Lady_Fox [76]
3 years ago
5

how many liters of a 60% antifreeze solution must be added to 8L of a 10% antifreeze solution to produce a 20% antifreeze soluti

on?
Chemistry
1 answer:
Tasya [4]3 years ago
5 0

Answer: 2Liters

Explanation:

The expression used will be :

M_1V_1+M_2V_2=M_3V_3

where,

M_1 = concentration of first antifreeze= 60%

M_2 = concentration of second  antifreeze= 10%

V_1 = volume of first antifreeze = x L

V_2 = volume of second antifreeze = 8 L

M_3 = concentration of final antifreeze solution= 20%

V_3 = volume of final antifreeze = (x+8) L

Now put all the given values in the above law, we get the volume of  antifreeze added

60\times x+10\times 8=20\times (x+8)

x=2L

Therefore, the volume of 60% antifreeze solution that must be added is 2L

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Which of the following provides the best analogy for an electron in an atomic orbital
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0.250 moles of NaCl is dissolved in 0.850 L of solution. What is the molar concentration?
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Considering the definition of molarity, the molar concentration is 0.294 \frac{moles}{liter}.

Molarity reflects the concentration of a solution indicating the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

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Molarity is expressed in units \frac{moles}{liter}.

In this case, you know:

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Replacing in the definition of molarity:

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