1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fenix001 [56]
1 year ago
15

A 10.0-g sample of magnesium reacts with oxygen to form 16.6 g of magnesium oxide. How many grams of oxygen reacted?

Chemistry
1 answer:
kodGreya [7K]1 year ago
3 0

6.6 grams of oxygen reacted with magnesium to give magnesium oxide.

<h3>What is law of conservation of mass?</h3>

When a chemical reaction takes place the total mass of reactants is always equal to the mass of products.As in a chemical reaction the atoms are neither created nor destroyed rather they rearrange themselves.

The reaction between magnesium and oxygen is as follows,

2 Mg+O₂\rightarrow2 MgO

According to the question, 10 g of magnesium is utilized to produce 16.6 g of magnesium oxide.In order to find mass of oxygen utilized ,

mass of oxygen=mass of magnesium oxide-mass of magnesium

substituting the given data,

mass of oxygen=16.6-10=6.6 g

Thus, 6.6 grams oxygen reacted to produce 16.6 grams of magnesium oxide.

Learn more about law of conservation of mass ,here:

brainly.com/question/13383562

#SPJ1

You might be interested in
How can water be used for energy ?
Fantom [35]

First one is B and the second one is C

6 0
3 years ago
Read 2 more answers
What state of matter has no visible shape and fills its container?
Ilia_Sergeevich [38]
I believe it is b. I hope this helps you
8 0
3 years ago
Read 2 more answers
Connect as many terms that you can think of. Each term should be related to
Ymorist [56]
Light PLEASE Thanks me I need points to ask questions
6 0
3 years ago
Read 2 more answers
A 56 g sample of peanut oil has a volume of 60.9 cm³. Calculate the density of the peanut oil. Remember to use the correct numbe
Ivan
0.92 because Mass divided by Volume = Density 
5 0
3 years ago
Read 2 more answers
In an ion with an unknown charge, the total mass of all the electrons was determined to be 2.19 ✕ 10−26 g, while the total mass
Ilya [14]

Answer:

\large \boxed{\text{Fe$^{{2+}}$}}

Explanation:

1. Number of electrons

\text{Number of electrons} = 2.19 \times 10^{-26}\text{ g} \times \dfrac{\text{1 electron}}{9.109 \times 10^{-28}\text{ g}} = \text{24 electrons}

2. Number of protons

\text{Number of protons} = 4.34 \times 10^{-23}\text{ g} \times \dfrac{\text{1 proton}}{1.673 \times 10^{-24}\text{ g}} = \text{26 protons}

3. Identify the ion

An atom with 26 protons is iron, Fe.

A neutral atom of iron would have 26 electrons.

The ion has only 24 electrons, so it has lost two. The ion must have a charge of +2.

\text{The symbol for the ion is $\large \boxed{\textbf{Fe$^{\mathbf{2+}}$}}$}

4 0
3 years ago
Other questions:
  • The question is in the picture below.
    14·1 answer
  • What substance is acting as the Brønsted-Lowry base in the forward reaction below? H2O + HCl yields H3O+ + Cl-
    14·1 answer
  • The half-life of the carbon isotope C-14 is approximately 5,715 years. What percent of a given amount remains after 300 years? R
    10·1 answer
  • Magnesium oxide can be produced by heating magnesium metal in the presence of oxygen. When 10.1 g of Mg reacts with 10.5 g of O2
    15·1 answer
  • When A is changing at a rate of -0.190 M⋅s−1 , how fast is B changing?
    14·1 answer
  • How many mole are in 2.84*10^22 molecules of h2
    9·1 answer
  • Students in a robotics class designed cars to race as their end of the year project. Students collected data on their cars and c
    11·1 answer
  • 2) A solution consists of 0.50 mole of CaCl2 dissolved i
    13·2 answers
  • If I have one mole of cupcakes, how many cupcakes do I have?
    14·1 answer
  • Gastric acid plays a key role in the digestion of proteins by activating digestive enzymes and often has a pH value in the range
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!