A 10.0-g sample of magnesium reacts with oxygen to form 16.6 g of magnesium oxide. How many grams of oxygen reacted?
1 answer:
6.6 grams of oxygen reacted with magnesium to give magnesium oxide.
<h3>What is law of conservation of mass?</h3>When a chemical reaction takes place the total mass of reactants is always equal to the mass of products.As in a chemical reaction the atoms are neither created nor destroyed rather they rearrange themselves.
The reaction between magnesium and oxygen is as follows,
2 Mg+O₂2 MgO
According to the question, 10 g of magnesium is utilized to produce 16.6 g of magnesium oxide.In order to find mass of oxygen utilized ,
mass of oxygen=mass of magnesium oxide-mass of magnesium
substituting the given data,
mass of oxygen=16.6-10=6.6 g
Thus, 6.6 grams oxygen reacted to produce 16.6 grams of magnesium oxide.
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Explanation:
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Equilibrium reaction of strontium sulfate and sodium sulfate follows the equation:
According to Le-Chateliers principle: If there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.
In the equilibrium reactions, hypochlorite ion is getting increased on the product side, so the equilibrium will shift in the direction to minimize this effect, which is in the direction of hydrogen hypochlorite.
Thus, the addition hypochlorite ions will shift the equilibrium in the left direction.
The dissociation of hydrogen hypochlorite is suppressed due to the common ion effect.