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sergiy2304 [10]
3 years ago
15

Choose all of the expressions that are equal to −9. |−9| −(−9) −|−9| −|9| the distance from zero to nine the opposite of nine

Mathematics
1 answer:
sergiy2304 [10]3 years ago
8 0

Answer:

<h2>|−9|,  −|−9| and −|9| </h2>

Step-by-step explanation:

Before we choose all the expression that is equal to -9, <em>we must understand that the modulus of a value can return both its positive and negative value</em>. For example, Modulus of b can either be +b or -b i.e |b| = +b or -b

Hence the following expression are all equal ro -9

a)  |−9| is equivalent to -9 because the absolute value of -9 i.e |−9| can return both -9 and 9

b)  −|−9| is also equivalent to -9. The modulus of -9 is also equal to 9, hence negating 9 will give us -9. This shows that  −|−9| = −|9| = −9

c)  −|9| is also equivalent to -9. This has been established in b above.

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Step-by-step explanation:

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Step-by-step explanation:


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Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
What is the solution for the equation -15=5(3y-10)-5y
marissa [1.9K]

Answer:

  • \Large\boxed{\sf{y=\dfrac{7}{2} }}

Step-by-step explanation:

Isolate the variable of y from one side of the equation.

-14=5(3y-10)-5y

<u>First, switch sides.</u>

\sf{5\left(3y-10\right)-5y=-15}

Use the distributive property.

<u>DISTRIBUTIVE PROPERTY:</u>

A(B-C)=AB-AC

5(3y-10)

Multiply by expand.

5*3y=15y

5*10=50

15y-50-5y

15y-5=10y

= 10y-50

10y-50=-15

Add by 50 from both sides.

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Solve.

10y=35

Then, you divide by 10 from both sides.

10y/10=35/10

Solve.

Divide the numbers from left to right.

35/10=7/2

y=7/2

Divide is another option.

7/2=3.5

\Longrightarrow: \boxed{\sf{y=\dfrac{7}{2}}}

  • <u>Therefore, the correct answer is y=7/2.</u>

I hope this helps. Let me know if you have any questions.

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3 years ago
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