Help with math question please thankksssss

Mathematics

1 answer:

Sedaia [141]3 years ago

7 0

X equals 1 and 2. When you put 1 into f(x) you get 2 and when you put 1 into g(x) you get 1 as well. The same for 2...but not the same for 3.

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A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1

kvasek [131]

Answer:

$CI=\{-0.2941,-0.0337\}$

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is $\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}$ where $\hat{p}_1$ and $n_1$ are the sample proportion and sample size of the first sample, and $\hat{p}_2$ and $n_2$ are the sample proportion and sample size of the second sample.

We see that $\hat{p}_1=\frac{87}{249}\approx0.3494$ and $\hat{p}_2=\frac{58}{113}\approx0.5133$ . We also know that a 98% confidence level corresponds to a critical value of $z^*=2.33$ , so we can plug these values into the formula to get our desired confidence interval:

$\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}$

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

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2 years ago

in order to use a chi-square test for goodness of fit the data must satisfy a multinomial setting. one condition for a multinomi

Hitman42 [59]

The multinomial setting goodness of fit test allows to check whether the distribution of a sample corresponding to a qualitative variable (or discrete quantitative variable) is consistent with the expected results.

The Chi-square goodness of fit test is a statistical hypothesis test used to determine whether a variable is likely to come from a specified distribution or not. It is often used to check whether the sample data is representative of the full population or is it biased.

The degrees of freedom for the chi-square goodness of fit is calculated by using the following formula: df = (r-1)(c-1) where r is the number of rows and c is the number of columns. The following conditions are the conditions required: The sampling method should be simple random sampling. The variable being observed is categorical. The expected value of the number of sample observations for each variable is at least 5.

Therefore, The multinomial setting goodness of fit test allows to check whether the distribution of a sample corresponding to a qualitative variable (or discrete quantitative variable) is consistent with the expected results.

To learn more about goodness of fit refer here

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1 year ago

PLEASE HELP WIL MARK BRAINLIEST MY DUDE

mihalych1998 [28]

Answer:

I think the answer is D

Step-by-step explanation:

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3 years ago