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Alisiya [41]
3 years ago
10

Number 10 I don’t know how to do

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0
<h2>Answer:</h2>

<u>Yes he is correct</u>

<h2>Step-by-step explanation:</h2>

Given a triangle ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side. In the words of Euclid: In any triangle two sides taken together in any manner are greater than the remaining one.

If we add the two sides 12 and 18 we get 30 so the third side must be greater than 30. He said greater than 6 so he is right too

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Brainliest if it is right
cupoosta [38]

Answer:

17.8

Step-by-step explanation:

All you have to do is 8.9 x 2 = 17.8

HOPE HIS HELPS

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2 years ago
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What is 1 3/5 - 5/6? Please Help
gizmo_the_mogwai [7]

Answer:

Exact Form:

\frac{23}{30}

Decimal Form:

0.76

Step-by-step explanation:

<em>Hope this helped and good luck <3</em>

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An unprepared student makes random guesses for 6 multiple choice questions that have selections a -
kirill [66]
 <span>P(at least 1 ) = 1 - P(exactly none) = 1 - (4/5)^6 = .738
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3 years ago
How do u find the answer to this
stepladder [879]
11^0 is 1.
11^2= 121

121/1= 121

Final answer: 121
6 0
3 years ago
Preliminary data analyses indicate that it is reasonable to use a t-test to carry out the specified hypothesis test. Perform the
Readme [11.4K]
<h2>Answer with explanation:</h2>

By considering the given information, we have

Null hypothesis : H_0: \mu=35.0

Alternative hypothesis : H_1: \mu\neq35.0

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.

\overline{x}=41.0    ;    \sigma= 3.7

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

i.e. t=\dfrac{41.0-35.0}{\dfrac{3.7}{\sqrt{20}}}=7.252112359\approx7.25

Degree of freedom : n-1 = 20-1=19

Significance level = 0.01

For two tailed,  Significance level =\dfrac{0.01}{2}=0.005

By using the t-distribution table, the critical value of t =t_{19, 0.005}=2.861

Since , the observed t-value (7.25) is greater than the critical value (2.861) .

So we reject the null hypothesis, it means we have enough evidence to support the alternative hypothesis.

We conclude that there is some significance difference between the mean score for sober women and 35.0.

3 0
3 years ago
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