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Alisiya [41]
3 years ago
10

Number 10 I don’t know how to do

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0
<h2>Answer:</h2>

<u>Yes he is correct</u>

<h2>Step-by-step explanation:</h2>

Given a triangle ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side. In the words of Euclid: In any triangle two sides taken together in any manner are greater than the remaining one.

If we add the two sides 12 and 18 we get 30 so the third side must be greater than 30. He said greater than 6 so he is right too

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The last answer I got for this was not help full. Please help. Will give brainliest.
dimulka [17.4K]
Suppose JJ = Jhalil , J = Joman

1 - JJ 860 J620

2 - JJ 870 J 670

3- JJ880 J 720

4- JJ890 J 770

5- JJ900 J 820

6- JJ910 J 870

7- JJ920 J 920 - Catched up

8- JJ 930 J 970

9- JJ940 J 1020

10- JJ 950 J 1070

11- JJ960 J 1120

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so a - week 7

b- Joman 

7 0
3 years ago
What is the value of y in the solution to the system of equations?
Nana76 [90]
The value of y is positive 8
4 0
3 years ago
Is -15 less than -7 plz I need so much help
DedPeter [7]
-15 is in fact less than -7. Here is a number line:

-15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5...

Let me know if you need clarification :)
4 0
3 years ago
Read 2 more answers
Which quadratic function in standard form has the values a = –3.5, b = 2.7, and c = –8.2?
sweet-ann [11.9K]

Answer:

f(x)=-3.5x²+2.7x - 8.2

Step-by-step explanation:

We have given:

a = -3.5 , b=2.7 and c= -8.2

We have to write  quadratic function in standard form.

We know that the standard form of quadratic function is:

f(x)=ax²+bx+c

where a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

We have the values a= -3.5 , b = 2.7 and c = -8.2

Substitute the values  in the standard form:

f(x)=-3.5x²+2.7x - 8.2

Therefore the answer is: f(x)=-3.5x²+2.7x - 8.2 ....

6 0
4 years ago
Find the product -a2 b2 c2 (a+b-c)
mina [271]
Use the distributive property:
a(c+b)=ab+ac
And
a^n\cdot a^m=a^{n+m}\\\\a=a^1

-a^2b^2c^2(a+b-c)=-a^2ab^2c^2-a^2b^2bc^2+a^2b^2c^2c=-a^3b^2c^2-a^2b^3c^2+a^2b^2c^3

7 0
3 years ago
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