Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
1.5-6-12n. 1-12n
2.-4+40x-35. -39+40x
3.-36x+6+6. 12-36x
4.40n-32+8n. 48n-32
5.7n-28-6. 34-7n
6.-16+20x+3x 23x-16
7. -2n-16+8. -2n-8
8.25b-25-1. 25b-26
9.-4n+15-6n. -10n+15
-1-3x+6. -3x+5
Let the number be x
15% = 90
1% = 6
100% = 6 x 100 = 600
Answer:
0.4929 = 49.29% probability that he voted in favor of Scott Walker
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Having a college degree.
Event B: Voting for Scott Walker.
They found that 57% of the respondents voted in favor of Scott Walker.
This means that 
Additionally, they estimated that of those who did vote in favor for Scott Walker, 33% had a college degree
This means that 
Probability of having a college degree.
33% of those who voted for Scott Walker(57%).
45% of those who voted against Scott Walker(100 - 57 = 43%). So

What is the probability that he voted in favor of Scott Walker?
0.4929 = 49.29% probability that he voted in favor of Scott Walker