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MatroZZZ [7]
3 years ago
13

Reduce to simplest formnegative 7/8 minus (negative 5/6)

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

(-21/24) - (-20/24) = -1/24

<em>Simplest Form of the Equation</em>

(-7/8) - (-5/6) = 0.04166666666

8x6= 48,

-7x6=-42

6x8= 48,

-5x8=40

(-42/48) - (-40/48)

Divide both sides by 2

(-21/24) - (-20/24) = -1/24

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Answer:

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Step-by-step explanation:

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3 years ago
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Can i get help working out 3x− 12 = 2x+ 3
Naddik [55]

Answer:

x = 15

Step-by-step explanation:

3x− 12 = 2x+ 3

3x-2x-12 = 3

x = 3+12

x=15

hope this helps! :)

5 0
3 years ago
Which of the sequences is an arithmetic sequence?
Dennis_Churaev [7]

Answer:

B. -3, -10, -17, -24, -31

Step-by-step explanation:

An Arithmetic sequence is defined as a set of numbers with a common difference. In answer choice B, it is seen that the difference between each number is seven.

A is incorrect as one to eight has a difference of seven, while the other numbers have a difference of eight.

C is incorrect as it skips the number 12 between 9 and 15, thus breaking the sequence.

D is incorrect as the numbers jump from positive to negative, thus not having a common difference.

Hope this helps!

7 0
3 years ago
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A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha
Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

  • The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
  • the radius r=5cm
  • Punch is being poured into the bowl
  • The height at which the punch is increasing in the bowl is \frac{dh}{dt} = 1.5
  • the exposed area is a circle, (since the bowl is a hemisphere)
  • the radius of this circle can be written as 'a'
  • what is being asked is the rate of change of the exposed area when the height h = 2 cm
  • the rate of change of exposed area can be written as \frac{dA}{dt}.
  • since the exposed area is changing with respect to the height of punch. We can use the chain rule: \frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}
  • and since A = \pi a^2 the chain rule above can simplified to \frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt} -- we can call this Eq(1)

Solution:

the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

\frac{da}{dt} = \frac{(r-h)(1.5)}{a}

and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

simplify,

\frac{dA}{dt} = 3 \pi (r-h)

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

5 0
3 years ago
Can anyone help me with this math problem?
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Lemme give you a cheap answer, by simply using the "compound interest formula", which is what that is, 2% compounded yearly

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plug in those values, and simplify
3 0
4 years ago
Read 2 more answers
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