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MatroZZZ [7]
3 years ago
13

Reduce to simplest formnegative 7/8 minus (negative 5/6)

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

(-21/24) - (-20/24) = -1/24

<em>Simplest Form of the Equation</em>

(-7/8) - (-5/6) = 0.04166666666

8x6= 48,

-7x6=-42

6x8= 48,

-5x8=40

(-42/48) - (-40/48)

Divide both sides by 2

(-21/24) - (-20/24) = -1/24

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How to comvert 5/8 into a decimal​
Maksim231197 [3]

To convert fractions into decimals simply divide the numerator (5) by the denominator (8). If you type in "5/8" into a calculator you will receive a compute of 0.625 which you can round to .6

6 0
3 years ago
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If f(x)3(=- Vx-3, complete the following statement:x + 2f(19) ==Answer here
Digiron [165]
Explanation

This exercise is about evaluating a function at a particular argument. To do that, we replace the variable with the argument in the formula of the function, and simplify.

Let's do that:

\begin{gathered} f(19)=\frac{3}{19+2}-\sqrt[]{19-3}, \\  \\ f(19)=\frac{3}{21}-\sqrt[]{16}, \\  \\ f(19)=\frac{1}{7}-4, \\  \\ f(19)=\frac{1-28}{7}, \\  \\ f(19)=-\frac{27}{7}\text{.} \end{gathered}Answerf(19)=-\frac{27}{7}\text{.}

8 0
1 year ago
A study was performed to investigate whether teens and adults had different habits when it comes to consuming meat-free meals. I
Elden [556K]

Answer:

H₀ should be rejected at CI 95% .

Then the proportion of adults with 95 % CI is bigger than the proportion of teen

Step-by-step explanation:

From adult sample:

n₂ = 2323

x₂ = 1601

p₂ = 1601 / 2323         p₂  = 0,689       or    p₂ = 68,9%

From teen sample:

n₁ = 875

x₁ = 555

p₁ = 555/ 875           p₁  = 0,634          or    p₁  = 63,4

Values of p₁  and  p₂   suggest that the proportion of adults consuming at least one meat free meal per week is bigger than teen proportion.

To either prove or reject the above statement we have to develop a difference of proportion test according to:

Hypothesis test:

Null Hypothesis                   H₀             p₁  =  p₂

Alternative Hypothesis       Hₐ             p₂  > p₁

So is a one-tail test to the right

We can establish a confidence interval of 95 % then  α = 5 %

or    α = 0,05

As the samples are big enough we will develop a z test

Then  z(c)  for α = 0,05   from z table is     z(c) = 1,64

To calculate z(s)

z(s) = ( p₂  -  p₁ ) / √p*q* ( 1/n₁  + 1/n₂ )

where p = ( x₁ + x₂ ) / n₁ + n₂       p = 555 + 1601 / 875 + 2323

p = 2156/3198       p = 0,674

and   q = 1 - 0,674        q = 0,326

z(s) = ( 0,689 - 0,634 ) / √0,674*0,326 ( 1/875 + 1 / 2323

z(s) = 0,055/ √ 0,2197 ( 0,00114 + 0,00043)

z(s) = 0,055/ √0,2197* 0,00157

z(s) = 0,055/ √ 3,45*10⁻⁴

z(s) = 0,055 / 1,85*10⁻²

z(s) = 5,5/1,85

z(s) = 2,97

Comparing  z(s) and z(c)     z(s) > z(c)

Then z(s) is in the rejection region we reject H₀.

We can claim that the proportion of adult eating at least one meat-free meal is bigger than the proportion of teen

6 0
3 years ago
How is finding the area of a trapezoid different from finding the area of a parallelogram and a triangle?
trasher [3.6K]
There are different formulas for each different shape.
8 0
3 years ago
1. IQ scores of statistics students have a standard deviation less than 15. A. H0:σ≤15, H1:σ&gt;15 B. H0:σ≥15, H1:σ&lt;15 C. H0:
grandymaker [24]

Answer:

1) For this case we want to check if the population deviation is less than 15( alternative hypothesis) and the system of hypothesis are:

H0: \sigma \geq 15

H1: \sigma

B. H0:σ≥15, H1:σ<15

2) For this case we want to check if the population mean \mu is at most 70000 (alternative hypothesis) and the system of hypothesis are:

H0: \mu \geq 70000

H1: \mu

C. H0:µ≥70,000, H1:µ<70,000

3) For this case we want to check if the population proportion p of all internet users that make online purchases is higher than 0.5 (alternative hypothesis) and the system of hypothesis are:

H0: p \leq 0.5

H1: p >0.5

D. H0:p≤0.5, H1:p>0.5

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

Solution to the problem

1) For this case we want to check if the population deviation is less than 15( alternative hypothesis) and the system of hypothesis are:

H0: \sigma \geq 15

H1: \sigma

B. H0:σ≥15, H1:σ<15

2) For this case we want to check if the population mean \mu is at most 70000 (alternative hypothesis) and the system of hypothesis are:

H0: \mu \geq 70000

H1: \mu

C. H0:µ≥70,000, H1:µ<70,000

3) For this case we want to check if the population proportion p of all internet users that make online purchases is higher than 0.5 (alternative hypothesis) and the system of hypothesis are:

H0: p \leq 0.5

H1: p >0.5

D. H0:p≤0.5, H1:p>0.5

7 0
3 years ago
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