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4 years ago

11

Which of the sequences is an arithmetic sequence?

2 answers:

Dennis_Churaev [7]4 years ago

7 0

Answer:

B. -3, -10, -17, -24, -31

Step-by-step explanation:

An Arithmetic sequence is defined as a set of numbers with a common difference. In answer choice B, it is seen that the difference between each number is seven.

A is incorrect as one to eight has a difference of seven, while the other numbers have a difference of eight.

C is incorrect as it skips the number 12 between 9 and 15, thus breaking the sequence.

D is incorrect as the numbers jump from positive to negative, thus not having a common difference.

Hope this helps!

11111nata11111 [884]4 years ago

7 0

Answer: “B”

Step-by-step explanation: An arithmetic sequence is a pattern where the same number is repeatedly added or subtracted. “B” would be the correct answer because each time, we have a common difference of -7 because we subtract 7 each time to get to our next term. We could also write this in recursive description as followed.

Starting at -3, subtract 7 to get to the next term.

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3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

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$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

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So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

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3 years ago

Honestly, I'm trying my best to solve this but my Math XL is being so rude.

Valentin [98]

<h3>Answer: 19</h3>

==============================================================

Explanation:

T is the midpoint of PQ, which means T splits PQ into two equal parts. Those parts being PT and TQ.

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Both PT and TQ are 19 units long to help confirm the answer.

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