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svlad2 [7]
3 years ago
14

Write the expression in exponential form logb c=a

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:c=b^a

Step-by-step explanation:

Logb c=a

In exponential form

c=b^a

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Step-by-step explanation:

on the y axis, go up seven and dot it. then from there go up 3 and right 1 and plot a point. then draw a line through both dots

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3 years ago
63 is 90% of what number? using double number lines to get the answer
iren2701 [21]
Since the 90% is 63. divide it by 9. then you would get value of 7. then multiple it by 10.
which is equal to 70. so 100% is 70.
7 0
3 years ago
Read 2 more answers
Jenny was in charge of selling tickets to a family fun night at her school
ra1l [238]
I’ve attached my work below for #4
5) 8% is equivalent to 8 cents so each item was $1.08
Than you know he spent 16.20 so you divided
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6) the moon is 250,000 miles away which is about driving around earth 10 times which would take 6 months (not sure about this one)

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4 0
3 years ago
What is the largest possible number of peopel at a party if no two of them have birthdays in the same month
lakkis [162]

Answer:

12

Step-by-step explanation:

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5 0
2 years ago
How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
2 years ago
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