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Lelechka [254]
3 years ago
8

Write the equation of a Line that is perpendicular to y=5/2x+3 and passes

Mathematics
1 answer:
koban [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\

        m_{2}= -1 ÷ m_{1}

               = -1*\frac{2}{5}=\frac{-2}{5}

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

                                                y - [5] = \frac{-2}{5}(x - [-3])\\

                                               y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\   y =\frac{-2}{5}x-\frac{6}{5}-5\\\\   y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}

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30 points and brainly
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4 0
3 years ago
3. A hive of bees contains 27 bees when it is first discovered. After 3 days, there are 36 bees. It is determined that the popul
Alex Ar [27]

Answer:

360

Step-by-step explanation:

Points to Note

When the beehive was discovered, there were 27 bees

After 3 days, the numbers of bee increased to 36

Progression Type : Exponential (also knows as geometry)

Number of bees after 30 days is unknown

First we need to get the rate of progression (increment or decrement) between the first day and the third day it was discovered

From the question, we have

T1 = 27 ------------- T1 represents number of bees initiallly (1st term)

T2 = 36 ------------- T2 represents 2nd term (number of bees after 3days)

T3 represents 3rd term (after additional 3 days; i.e. 6 days)

T4 represents 4th term (after 12 days)

If you follow this progression, you'll noticed that

T10 = Number of bees on the 30th day

Since, it's an exponential progression; we have to divide to get the rate of progression

R = 36/27 ------------ R represents Rate of progress (also known as common radius)

R = 4/3

Using this progression formula

Tn = aR^(n-1)

Where a = T1 = 1st term = 27

R = Rate of progression = 4/3

n = Number of term = 10

Substituting these values in the progression formula

T10 = 27 * (4/3) ^(10-1)

T10 = 27 * (4/3)^9

T10 = 27 * 262144/19683

T10 = 7077888/19683

T10 = 359.594

T10 = 360 (approximated)

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3 years ago
Read 2 more answers
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Read 2 more answers
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nordsb [41]

Answer:

The scalar used does not exist in the real number system.

Step-by-step explanation:

The ratio 16:14 is not equivalent to the ratio 64:60 because the scalar used does not exist in the real number system.

Note, that the ratio 64:60 can be scaled down by 4 to be the ratio 16:15, which is not the ratio 16:14.

In order to scale 64:60 to 16:14 or vise versa, you'd have to use a number that simply does not exist in the real number system.

Cheers.

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2 years ago
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