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Studentka2010 [4]
2 years ago
14

PLEASE HELP ME OUT PLEASE AND I WILL GIVE BRAINLIES!!!!!!

Mathematics
1 answer:
vodka [1.7K]2 years ago
3 0

that is so easy your answer is 21

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What is the value of the number 4 on 264,807
Kruka [31]
The value of 4 is 4,000 (four thousand)
5 0
3 years ago
X + 8 + 2x <= 2x + 13
sergejj [24]

Answer:

X = 15

Step-by-step explanation:

We move all terms to the left:

<em>x+8+2x-(2x+13)=0</em>

We add all the numbers together, and all the variables:

<em>3x-(2x+13)+8=0</em>

We get rid of parentheses:

<em>3x-2x-13+8=0</em>

We add all the numbers together, and all the variables:

<em>x-5=0</em>

We move all terms containing x to the left, all other terms to the right:

<em>x=5</em>

5 0
3 years ago
A set of rules used to evaluate expressions with more than one operation is the..
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Answer:

Order of Operations

Step-by-step explanation:

8 0
4 years ago
A drug that it will decrease the bacteria cells by 5% every hour. If you start with 1500 bacteria cells, how many will be presen
scZoUnD [109]

after 8 hours there are 995 bacteria cells left

let y be the amount after 8 hours

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y = 1500 × (0.95)^{8} = 995




5 0
3 years ago
Consider the following sets of matrices: M2(R) is the set of all 2 x 2 real matrices; GL2(R) is the subset of M2(R) with non-zer
defon

Answer:

Step-by-step explanation:

REcall the following definition of induced operation.

Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.

So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.

For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).

Case SL2(R):

Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So

\text{det(AB)} = \text{det}(A)\text{det}(B)\neq 0.

So AB is also in SL2(R).

Case GL2(R):

Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So

\text{det(AB)} = \text{det}(A)\text{det}(B)=1\cdot 1 = 1.

So AB is also in GL2(R).

With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).

7 0
3 years ago
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