1.7a + 0.3a = 4/5 Please help....
2 answers:
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The answer is:
The rate of change is not constant and increases then decreases over time. The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.
Here's how:
The rate of change of the function is defined and calculated as (refer to the statement beloew):
r = [change in height] / {change in time]
For the Table:
refer to the attached picture.
The table shows the calculations for the rate of change (r) for each interval given.
And for the Conclusion,
Refer to the table and notice that in the third ans fifth columns show that:
The rate of change is not constant and increases then decreases over time. The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.
The rate of change is not constant and increases then decreases over time. The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.
Here's how:
The rate of change of the function is defined and calculated as (refer to the statement beloew):
r = [change in height] / {change in time]
For the Table:
refer to the attached picture.
The table shows the calculations for the rate of change (r) for each interval given.
And for the Conclusion,
Refer to the table and notice that in the third ans fifth columns show that:
The rate of change is not constant and increases then decreases over time. The height of the ball above ground gets larger until 1.25 seconds and then gets smaller after that time.
Answer:
D2=21/24 mile
Step-by-step explanation:
Her it is not specified if it is base or height, it only talks about dimensions, so let's work with dimensions
A=1/12
D1=4/21mile, D2=?
Area of a triangle
A=((D1*D2)/2) → 2A=D1*D2 → D2=2A/D1 so D2=(2*1/12)/(4/21) =(1/6)/(4/21) = (1*21)/(6*4)=21/24 mile