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SSSSS [86.1K]
3 years ago
15

Roland's Boat Tours sells deluxe and economy seats for each tour it conducts. In order to complete a tour, at least 14 economy s

eats must be sold and at least 5 deluxe seats must be sold. The maximum number of passengers allowed on each boat in 45. Roland's Boat Tours makes $30 profit for each economy seat sold and $25 profit for each deluxe seat sold. What is the maximum profit from one tour?
Mathematics
1 answer:
leonid [27]3 years ago
4 0
The maximum profit would be $1325. Since they make less profit on deluxe seats, you want to get as few of those as possible. You also want to get as many people on the boat as possible, which is 45. The minimum number of deluxe seats you could sell is 5, so that's what we'll use for the max. profit. They make $25 off of each of those seats so 5 times $25 is $125. That leaves 40 economy seats, with a profit of $30 per seat. You have 40 spots left open, so we'll sell 40 economy seats, which will meet your minimum of 14 economy seats. 40 times $30 is $1200. Add $125 and $1200 to get $1325 and you have your maximum profit!
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\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

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Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

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