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vampirchik [111]

3 years ago

9

If a pair of shoes costs $52.50 including a 7.25% tax, what is the original cost of the item before taxes are added? No other sy

mbols other than the number rounded to the second decimal.

1 answer:

zheka24 [161]3 years ago

3 0

Answer:

56.31

Step-by-step explanation:

A 7.25% tax is $3.81

52.50-3.81+48.69

Hope it helps!

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2 + 2 x 0<br><br> Anyone wanna join my pad✨let ?

erik [133]

Answer:

2

Step-by-step explanation:

6 0

3 years ago

Ok so i have to write something

kap26 [50]

(11/3-7/4)/[3.4-(1/2+2/3*3/2)]

First I converted fractions to mixed numbers.

11/3-7/4 / 3.4-3/2

Then, I solve the inside of the parentheses.

23/12 / 3.4-3/2

Continue to simplify

Convert to decimals

1.91667/1.9

Hope this helps

6 0

3 years ago

Pls pls pls help <br>Find the perimeter and the area

Illusion [34]

Answer:

Perimeter = 42 units Area = 57.73 square units

Step-by-step explanation:

Perimeter of an Astroid = 6l ---> 6 x 7 = 42 units

Area of an Astroid = (3 x pi x a^2)/8 = 57.73 square units

3 0

3 years ago

Kyle's mom gave him $25 for the carnival. If his

dimulka [17.4K]

8+0.75x=25
0.75x=25(-8)
0.75x=17
17/0.75= 22.666
He can ride a total of 22 rides

7 0

3 years ago

Diagram 5 shows a right cylinder with a diameter of 2xcm. Given that the total surface area of the cylinder is 96cm³.Find the ma

Paraphin [41]

Given:

The diameter of the right cylinder is 2x cm.

The total surface area is 96 cm cube.

The radius is calculated as,

$\begin{gathered} r=\frac{d}{2} \\ r=\frac{2x}{2} \\ r=x\text{ cm} \end{gathered}$

The total surface area is,

$\begin{gathered} S=2\pi rh+2\pi(r)^2 \\ 96=2\pi xh+2\pi(x^2) \\ h=\frac{96-2\pi(x^2)}{2\pi x} \end{gathered}$

Volume is,

$\begin{gathered} V=\pi(r)^2h \\ =\pi(x^2)\frac{96-2\pi(x^2)}{2\pi x} \\ =\frac{x(96-2\pi(x^2)}{2} \end{gathered}$

Now, differentiate with respect to x,

$\begin{gathered} \frac{dV}{dx}^{}=\frac{d}{dx}(\frac{x(96-2\pi(x^2)}{2}) \\ =\frac{d}{dx}\mleft(x\mleft(-\pi x^2+48\mright)\mright) \\ =\frac{d}{dx}\mleft(x\mright)\mleft(-\pi x^2+48\mright)+\frac{d}{dx}\mleft(-\pi x^2+48\mright)x \\ =1\cdot\mleft(-\pi x^2+48\mright)+\mleft(-2\pi x\mright)x \\ =84-3\pi(x^2)\ldots\ldots\ldots\ldots\text{.}(1) \end{gathered}$

Now,

$\begin{gathered} \frac{dV}{dx}=0 \\ 84-3\pi(x^2)=0 \\ x^2=\frac{16}{\pi} \\ x=\sqrt[]{\frac{16}{\pi}} \end{gathered}$

Now, differentiate (1) with respect to x again,

$\begin{gathered} \frac{d^2V}{dx^2}=\frac{d}{dx}(84-3\pi(x^2)) \\ =-6\pi x \\ At\text{ x=}\sqrt[]{\frac{16}{\pi}} \\ \frac{d^2V}{dx^2}=-6\pi\sqrt[]{\frac{16}{\pi}}$

Since, the double derivative is negative.

$So,\text{ the volume is maximum at }\sqrt[]{\frac{16}{\pi}}$

So, the volume becomes,

$\begin{gathered} V=\pi(x^2)h \\ V=\pi(\sqrt[]{\frac{16}{\pi}})^2h \\ V=\frac{16h}{\pi} \end{gathered}$

Answer: maximum volume of the cylinder is,

6 0

1 year ago