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Readme [11.4K]
3 years ago
10

Is y=x^3 a solution of the differential equation yy'=x^5+y

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

No; we have y=x^3\implies y'=3x^2. Substituting these into the DE gives

3x^5=x^5+x^3

which reduces to x^3=0, true only for x=0.

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I really need help with this
aniked [119]

Answer:

5√202

Step-by-step explanation:

By Pythagoras theorem,

x^2 = 45^2 + 55^2

= 2025 + 3025

x^2 = 5050

x = 5√202

5 0
3 years ago
5000 containers are stacked 20 wide and 50 long on a ship. How many containers high are they? Pls answer and give explanation, t
shutvik [7]

Answer:

5 containers high

Step-by-step explanation:

Given that :

Given :

Width = 20 containers

Length = 50 containers

Total containers = 5000

Hence,

Total containers = width * length * height

5000 = 20 * 50 * height

5000 = 1000 * height

Height = 5000 / 1000

Height = 5 containers

3 0
3 years ago
Bro no one cares<br> Bro no one cares<br> Bro no one cares
Aleonysh [2.5K]

Answer:

bro no one cares

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
During a period of 30 working days, Deborah was late 80% of the time. How many days was she late?
erik [133]
Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.

Num days late = 0.8 * 30=24

So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
8 0
2 years ago
What are the solutions of 3(x – 4)(2x – 3) = 0? Check all that apply.
RSB [31]
The answer will 3/2 and 4 :)
8 0
3 years ago
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