Is y=x^3 a solution of the differential equation yy'=x^5+y
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Hello,
x= amount of flour that she poured in the canister
there was 5,026 grams of flour, and now: 5,026+x
In the bag there was 4,158, now: 4,158
I says that as a result the mass of the flour in the canister is twice the mass of the flour left in the bag, so:
So, she poured 1,096.67 grams, we subtract this from the initial amount in the bag and we have the answer:
Answer: there is 3,061.33 grams of flour in the bag
x= amount of flour that she poured in the canister
there was 5,026 grams of flour, and now: 5,026+x
In the bag there was 4,158, now: 4,158
I says that as a result the mass of the flour in the canister is twice the mass of the flour left in the bag, so:
So, she poured 1,096.67 grams, we subtract this from the initial amount in the bag and we have the answer:
Answer: there is 3,061.33 grams of flour in the bag