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Readme [11.4K]
3 years ago
10

Is y=x^3 a solution of the differential equation yy'=x^5+y

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

No; we have y=x^3\implies y'=3x^2. Substituting these into the DE gives

3x^5=x^5+x^3

which reduces to x^3=0, true only for x=0.

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