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Readme [11.4K]
2 years ago
10

Is y=x^3 a solution of the differential equation yy'=x^5+y

Mathematics
1 answer:
shepuryov [24]2 years ago
3 0

No; we have y=x^3\implies y'=3x^2. Substituting these into the DE gives

3x^5=x^5+x^3

which reduces to x^3=0, true only for x=0.

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Can somebody help me in this one :)
MissTica

Answer:

A) f(x) = 6x + 14

Step-by-step explanation:

6(1) + 14 = 20

6 + 14 = 20

6(1.5) + 14 = 23

9 + 14 = 23

6(2) + 14 = 26

12 + 14 = 26

and so on...

5 0
2 years ago
Read 2 more answers
×WILL MARK AS BRAINLIEST×<br>Solve the equation for b, d and x
Lera25 [3.4K]
Solve for d:
(3 (a + x))/b = 2 d - 3 c
(3 (a + x))/b = 2 d - 3 c is equivalent to 2 d - 3 c = (3 (a + x))/b:
2 d - 3 c = (3 (a + x))/b
Add 3 c to both sides:
2 d = 3 c + (3 (a + x))/b
Divide both sides by 2:
Answer: d = (3 c)/2 + (3 (a + x))/(2 b)


-----------------------------

Solve for x:
(3 (a + x))/b = 2 d - 3 c
Multiply both sides by b/3:
a + x = (2 b d)/3 - b c
Subtract a from both sides:
Answer:  x = (2 b d)/3 + (-a - b c)

____________________________


Solve for b:
(3 (a + x))/b = 2 d - 3 c
Take the reciprocal of both sides:
b/(3 (a + x)) = 1/(2 d - 3 c)
Multiply both sides by 3 (a + x):
Answer: b = (3 (a + x))/(2 d - 3 c)
5 0
3 years ago
a. Determine whether the Mean Value Theorem applies to the function f (x )equals ln 15 xf(x)=ln15x on the given interval [1 comm
ivolga24 [154]

Answer:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

c = e-1 \\ = 1.71828

Step-by-step explanation:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

You are looking for a point c   such that

\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}

You have to solve for c  and get that

c = e-1 \\ = 1.71828

5 0
3 years ago
Identify the polynomial. <br><br> x 3 - y 3 + z
vekshin1
(X 3-y) (3+z)
That's the two polynomials
8 0
3 years ago
Read 2 more answers
What is the solutions for y=3x-5 and y=x-3
MArishka [77]

Answer: x=1, y=-2

Step-by-step explanation:

System

y=3x-5

y=x-3

3x-5=x-3

3x-x=-3+5

2x=2

x=2:2=1

y=x-3=1-3=-2

4 0
3 years ago
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