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Readme [11.4K]
3 years ago
10

Is y=x^3 a solution of the differential equation yy'=x^5+y

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

No; we have y=x^3\implies y'=3x^2. Substituting these into the DE gives

3x^5=x^5+x^3

which reduces to x^3=0, true only for x=0.

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It neve mentions how much of his farm he uses, but assuming he uses all of it
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5 0
3 years ago
Given: AE = 3, CE = 5 and ED is 4 less than EB find EB. Please give a step-by-step explanation. The best answer will receive bra
alisha [4.7K]

Answer:

EB = 10

Step-by-step explanation:

For this problem, you can use the power of a point, in the situation where two secants intersect in the interior of a circle. The formula is as follows:

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simplify,

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Since the value of EB is x, EB = 10.

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3 years ago
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Answer:

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3 0
2 years ago
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Answer:

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