According to Avogadro's number there are 62.53 atoms of chlorine in 1.1x 10
moles of Cl atoms.
<h3>What is Avogadro's number?</h3>
Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number or number of moles×Avogadro's number.
ON substitution in above formula number of atoms=1.1×10²¹×6.023×10²³=62.53 atoms
Thus, there are 62.53 chlorine atoms in 1.1x 10 moles of Cl atoms.
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Answer:
The general formula for an acid is HnX where H stands for hydrogen, n stands for the number of hydrogen ions, and X stands for the monatomic or polyatomic ions ( since those are negative charged ions, they are called anions).
Explanation:
The general formula for an acid is HnX) where H stands for hydrogen, n stands for the number of hydrogen ions, and X stands for the monatomic or polyatomic ions ( since those are negative charged ions, they are called anions).
An example is H2SO4, also called sulfuric acid
It shows that H2SO4 has 2 hydrogen atoms, so in the formula HnX n=2
X fro H2SO4 is SO42-, it's a polyatomic ion. Since it has a negative charge of 2- it needs 2 hydrogen atoms to bind and form H2SO4
Answer: 
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as
The equation for the ionization of the 
is given as:
When the solubility of is S moles/liter, then the solubility of 
will be S moles/liter and solubility of 
will be 2S moles/liter.
By stoichiometry of the reaction:
1 mole of gives 1 mole of 
and 2 moles of
![K_{sp}=[Ba^{2+}][F^{-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BBa%5E%7B2%2B%7D%5D%5BF%5E%7B-%7D%5D%5E2)
Thus 
for is
That would be an ionic bond since it has electrons to spare, rather than a convalent bond where all the electrons are taken up thus it is not a good conductor
