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Lena [83]
3 years ago
7

PLEASE HELP ME!

Chemistry
2 answers:
Murljashka [212]3 years ago
8 0

Answer:

hey Hanna .  

do you remember me?

im turkish

I guess you lived in western karolina

Was your name hanna or allecia or alex?

have your rabbits grown?

Explanation:

Allisa [31]3 years ago
7 0

The neutralization reaction is expressed as:

2KOH + H2SO4 = K2SO4 + 2H2O

We are given the volume and the concentration of the KOH that is used in the reaction. We use this and the relations from the reaction to determine the concentration of the acid.

0.150 mol KOH / L ( .025 L ) ( 1 mol H2SO4 / 2 mol KOH ) = 0.00188 mol H2SO4

Concentration of acid = 0.00188 mol / .015 = 0.125 M of sulfuric acid

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Answer:

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Explanation:

Step 1: Calculate the concentration of Mg²⁺ coming from Mg(NO₃)₂

Mg(NO₃)₂ is a strong electrolyte and the molar ratio of Mg(NO₃)₂ to Mg²⁺ is 1:1. The initial molar concentration of Mg²⁺ is 1/1 × 0.36 M = 0.36 M.

Step 2: Make an ICE chart for the solution of MgF₂

        MgF₂(s) ⇄ Mg²⁺(aq) + 2 F⁻(aq)

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The solubility product constant is:

Ksp = [Mg²⁺] × [F⁻]² = (0.36+S) × (2S)²

Since S <<< 0.36, 0.36+S ≈ 0.36.

Ksp = 0.36 × 4S² = 8.4 × 10⁻⁸

S = 2.4 × 10⁻⁴ M

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