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andreev551 [17]
3 years ago
12

Can someone help me plz

Mathematics
1 answer:
Oliga [24]3 years ago
7 0

Answer:

6^(7/3)

Step-by-step explanation:

Given 6^2 * cubed_root(6).

The cube root is also equal to 6^1/3

[Multiply the terms, add the powers]

6^2 * 6^(1/3) = 6^(2 + 1/3) = 6^(7/3)

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Answer:

n=\frac{0.3(1-0.3)}{(\frac{0.01}{1.96})^2}=8067.36  

And rounded up we have that n=8068

Step-by-step explanation:

The margin of error for the proportion interval is given by this:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

We want for this case a 95% of confidence desired, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

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The margin of error for this case is ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

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What is the domain and range of this function?
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