3 years ago

Please help me with this and I need the work shown out please

Mathematics

1 answer:

givi [52]3 years ago

5 0

Please note that you have to use the reason vert. opp. angles to find x, hope it helps:)

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A fish tank has a base area of 45cm2 and is filled with water to a depth of 12cm.If the height of the tank is 25cm, how much wat

stepladder [879]

Answer:

Step-by-step explanation:

v = 45 * 12

v = 540cm³

To fill the tank,

v = 45 * 25

v = 1,125cm³

I'm not quite sure what the exact question is so i'll answer both;

1.) The volume of water required to fill the tank from empty = 1,125cm³

2.) The volume of water required to fill the tank from it's current level is

1,125cm³ - 540cm³ = 585cm³

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3 years ago

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Step-by-step explanation:

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3 years ago

10 1/8 + (3 5/8+2 7/8)

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In this exercise, consider a particle moving on a circular path of radius b described by r(t) = b cos(ωt)i + b sin(ωt)j, where ω

Bingel [31]

Answer:

Acceleration of the particle = $bw^{2}$

Step-by-step explanation:

We are given the position vector of a particle moving in a circle of radius b units.

r(t) = b cos(ωt)i + b sin(ωt)j

Velocity , v = $\frac{dr}{dt}$ = -bω sin(ωt)i + bω cos(ωt)j

The magnitude of velocity, v = $\sqrt{v_x^{2} +v_y^{2} }$

Squaring both sides,

$v^{2} = b^{2} w^{2}(sin^{2}(wt)+cos^{2}(wt))$

Since $sin^{2}(wt)+cos^{2}(wt))$ = 1

$v^{2} = b^{2}w^{2}$

The acceleration towards the centre is called the centripetal acceleration and is given by

a = $\frac{v^{2} }{r}$

a = $\frac{b^{2}w^{2}}{b}$

a = $bw^{2}$

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3 years ago