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Ainat [17]
3 years ago
15

Please help me with this and I need the work shown out please

Mathematics
1 answer:
givi [52]3 years ago
5 0
Please note that you have to use the reason vert. opp. angles to find x, hope it helps:)

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Which parent function is represented by the graph?
zhenek [66]

Answer:

quadratic parent function

Step-by-step explanation:

squares cannot be negative no matter what you cannot square a number into a negative number which is why there are no negative y values because y is a function of X

4 0
2 years ago
Find the distance between the points. (0, 4) and (3, 0)
katrin [286]

I'm not sure but I think it's 5

3 0
2 years ago
Nick can read 3 pages of his book in 1 minute. At this rate how many pages can he read in 30 minutes?
g100num [7]

Answer:

90

Step-by-step explanation:

3/1=3

30x3=90

5 0
3 years ago
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
What is the difference between 49.2 and 12.3
Sauron [17]

Answer:

49.2 - 12.3 = 36.9

Step-by-step explanation:

Difference in Math terms means Subtract

5 0
2 years ago
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