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gavmur [86]
4 years ago
12

There are 16 sixth graders and 20 seventh graders in the Robotics Club. For the first project, the club sponsor wants to organiz

e the club members into equal-size groups. Each group will have only sixth graders or only seventh graders. How many students will be in each group if each group has the greatest possible number of club members?
Mathematics
1 answer:
polet [3.4K]4 years ago
7 0
Because you cannot add the two numbers you must find a common denominator for 16 and 20. This answer is 4. The greatest number of group members possible is 4.
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Simplify the expression by combining like terms. <br> 2x + 4y + 6 + 2y - 5 + 3x 
gtnhenbr [62]
I think the answer is 5x + 6y + 1
8 0
3 years ago
CAN YOU SEE THE PHTO IF YOU CAN PLEASE HELP WHAT IS THE AREA HELPPPPPPP
finlep [7]

Answer:

Give me the side lengths or we have a problem

Step-by-step explanation:

8 0
3 years ago
Gabrielle is traveling to Mexico and needs to exchange $440 into Mexican pesos. If each dollar is worth 11.84 pesos, how many pe
alexira [117]

Answer:

5209.60 pesos

Step-by-step explanation:

$440 x 11.84= 5209.60

6 0
3 years ago
Ben, Tim, and Sam have to do a certain job. Ben can finish the job in 5 hours. Tim can finish the job in 6 hours. Sam can finish
Brut [27]

x is 7.5 hours

Step-by-step explanation:

Ben, Tim, and Sam have to do a certain job

  • Ben can finish the job in 5 hours
  • Tim can finish the job in 6 hours
  • Sam can finish the job in x hours
  • The three of them can finish the job in 2 hours if they work together

We need to find x

∵ Ben can finish the job in 5 hours

∴ The rate of Ben = \frac{1}{5}

∵ Tim can finish the job in 6 hours

∴ The rate of Tim = \frac{1}{6}

∵ Sam can finish the job in x hours

∴ The rate of Sam = \frac{1}{x}

They will working together to finish the job in two hours, that means the sum of their rate is equal to 1/2

∵ They can finish the job in 2 hours if they work together

∴ \frac{1}{5}+\frac{1}{6}+\frac{1}{x}=\frac{1}{2}

To add the fractions find the LCM for all denominators to make all fractions with same denominators

∵ The LCM of 5, 6 ans x is (5 × 6 × x) = 30 x,

- Divide it by each denominator to find the new numerators

∵ 30 x ÷ 5 = 6 x , 30 x ÷ 6 = 5 x , 30 x ÷ x = 30

- Change all the denominators to 30 x and then write the new

   numerators of each fraction

∴ \frac{6x}{30x}+\frac{5x}{30x}+\frac{30}{30x}=\frac{1}{2}

Add the numerators and put the sum over 30 x

∵ \frac{11x+30}{30x}=\frac{1}{2}

- By using cross multiplication

∴ 2(11 x + 30) = 1(30 x)

- Simplify the both sides

∴ 22 x + 60 = 30 x

- Subtract 22 x from both sides

∴ 60 = 8 x

- Divide both sides by 8

∴ 7.5 = x

∴ The value of x is 7.5 hours

x is 7.5 hours

Learn more:

You can learn more about the word problems in brainly.com/question/10712420

#LearnwithBrainly

5 0
4 years ago
Look and solve plz herhenh
vodomira [7]

Answer:

s = 33

Step-by-step explanation:

99=3s

(99/3) = s

s=33

5 0
3 years ago
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