Answer:
one real solution
Step-by-step explanation:
We can use the discriminant to find the types of solutions
b^2 -4ac where ax^2 +bx+c=0
Since
x^2 -8x+16 =0
we know a=1 b=-8 and c=16
(-8)^2 - 4(1)(16)
64 -64 = 0
If the discriminant > 0 we have two real solutions
If the discriminant = 0 we have 1 real solutions
If the discriminant < 0 we have two complex solutions
Since it equals zero, we have one real solution
Answer: add the 2 to both sides and then eliminate the the two I think
Step-by-step explanation
Hi, thank you for posting your question here at Brainly.
A rectangular hyperbola is characterized as that having perpendicular asymptotes. This occurs when the semi-major axis (a) is equal to the semi-minor axis (b). This is also called an equilateral hyperbola or right hyperbola.