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Kryger [21]
3 years ago
12

A pattern follows the rule "Starting with three, every consecutive line has 2 less than twice the previous line."

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0
"Starting with three, every consecutive line has 2 less than twice the previous line."

this statement means that
your staring line has 3 marbles. You multiply the 3 marblesby 2 so
3x2=6
And then you minus it by 2
6-2=4

which means that you'll get 4 marbles for the next line.

So to get your 6th line, you count how many marbles is on the 5th line but since your diagram doesn't have the 5th line you have to figure out the 5th line by counting how.many marbles is on the 4th line.

4th line = 10 marbles

10×2=20
20-2=18

5th line = 18

18×2=36
36-2=34

So the 6th line has 34 marbles.
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What is 5(4x + 3.5) equivalent to?
sergejj [24]

Answer:

The answer is  

20x + 17.5

Step-by-step explanation:

Multiply the 5 by the numbers inside the parenthesis.

5 x 4x

5 x 3.5

3 0
3 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
An animal reserve has 40,000 elk. The population increases 11% a year. How long tell the population is equal to 80,000. If someo
sukhopar [10]

Answer:

7 years (This answer is to the nearest year)

Step-by-step explanation:

The way you could work this out is by trial and error. 11 % a year means that its population increases by 4400 annually. 40,000 X 1.11^1 gives you the amount it would be after one year (44000). I got the 1.11 because of the percentage (0.11) plus the amount you need to do percentage increase (1). Then all you do is keep on going up till you hit the number you need (80,000) after about 7 years the total would have hit 80,000 and would have actually went past it (83046)

8 0
3 years ago
According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

<em>Let </em>\hat p<em> = sample proportion of Americans who can order a meal in a foreign language</em>

The z-score probability distribution for sample proportion is given by;

          Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.06) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } } ) = P(Z > 0.85) = 1 - P(Z \leq 0.85)

                                                               = 1 - 0.80234 = <u>0.19766</u>

<em>Now, in the z table the P(Z  </em>\leq <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0
3 years ago
Translate the phrase into a variable expression: twice the sum of a number and 5
DIA [1.3K]

Answer:

'Twice the sum of a number and 5' can be translated into variable expression such as:

  • 2(n + 5)

Step-by-step explanation:

Given the phrase

<em>Twice the sum of a number and 5</em>

First, let us breakdown the English Phrase

Let the number be = n

The sum of a number 'n' and 5 = n + 5

now, twice the sum of a number and 5 can be determined by multiplying (n+5) with 5.

Thus,

'<em>Twice the sum of a number and 5</em>' can be translated into variable expression such as:

  • 2(n + 5)
7 0
3 years ago
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