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MariettaO [177]
3 years ago
7

The system of equations y=-1/2 x + 4 and y= 2x - 1 is shown on the graph below According to the graph what is the solution to th

is system of equations?

Mathematics
2 answers:
makkiz [27]3 years ago
8 0

Answer:

the answer is where the 2 points intersect... A. (2,3)

Step-by-step explanation:

PtichkaEL [24]3 years ago
6 0

Answer:

The correct option is A.

Step-by-step explanation:

The given system of equations is

y=-\frac{1}{2}x+4

y=2x-1

All the points on a line is are the solutions of the equation of line.

From the graph it is clear that the lines intersect each other at point (2,3). It means both the lines passes through the point (2,3) and point (2,3) is the solution of given system of equations.

Since (2,3) is the solution of given system of equations, therefore the correct option is A.

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mart [117]

Answer:

Probability that the mean service time is between 1 and 2 hours is 0.96764.

Step-by-step explanation:

We are given that a systematic random sample of 100 service appointments has been collected.

The 100 appointments showed an average preparation time of 90 minutes with a standard deviation of 140 minutes.

<u><em>Let </em></u>\bar X<u><em> = sample mean service time</em></u>

The z-score probability distribution for sample mean is given by;

                             Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = average preparation time = 90 minutes

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           n = sample of appointments = 100

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, probability that the mean service time is between 60 and 120 minutes is given by = P(60 minutes < \bar X < 120 minutes)

P(60 minutes < \bar X < 120 minutes) = P(\bar X < 120 min) - P(\bar X \leq 60 min)  

  P(\bar X < 120 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{120-90}{\frac{140}{\sqrt{100} } } ) = P(Z < 2.14) = 0.98382

  P(\bar X \leq 60 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{60-90}{\frac{140}{\sqrt{100} } } ) = P(Z \leq -2.14) = 1 - P(Z < 2.14)

                                                        = 1 - 0.98382 = 0.01618

<em>The above probability is calculated by looking at the value of x = 2.14 in the z table which has an area of 0.98382.</em>

Therefore, P(60 min < \bar X < 120 min) = 0.98382 - 0.01618 = <u>0.96764</u>

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