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3 years ago

The answer is b. I didn't see it on here so helping look a picture

Mathematics

1 answer:

Advocard [28]3 years ago

3 0

Answer:

B: Correct

Step-by-step explanation:

Plz give brainliest

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I think your answer would be 12x - 2

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Grapes cost $3.25 per pound. Darius paid a total of $26 for grapes.

Dmitry [639]

Answer:He buys 8 pounds

Step-by-step explanation:

You can either just add up the $3.25 until you get to the end-price, but that wont always work for every problem. The best way is to divide the 26 with the 3.25 in a written devision.

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3 years ago

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

3 years ago

The answer is b. I didn't see it on here so helping look a picture​

The answer is b. I didn't see it on here so helping look a picture