3 years ago

How would you write an equation of a circle that is (-3,2) with a radius of 5

Mathematics

1 answer:

ivann1987 [24]3 years ago

7 0

Answer:

(x+3)^2 + (y-2) ^2 = 25

Step-by-step explanation:

Equation of a circle: (x-h)^2 + (y-k)^2 = r^2

Center at (h,k)

Radius=r

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Use intercepts to graph the line described by each equation

Anon25 [30]

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6 0

3 years ago

Find the coordinates of point S that lies along the directed line segment from R(-14, -1) to T(4, -13) and partitions the segmen

horsena [70]

Check the picture below.

I'd like to point out, is 1:5 from R to T, since that matters, that way we know the ratio from RS is the 1 and the ratio ST is the 5.

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
R(-14,-1)\qquad T(4,-13)\qquad \qquad 1:5
\\\\\\
\cfrac{RS}{ST} = \cfrac{1}{5}\implies \cfrac{R}{T} = \cfrac{1}{5}\implies 5R=1T
\implies 
5(-14,-1)=1(4,-13)\\\\
-------------------------------\\\\$

$\bf { S=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\\
-------------------------------\\\\
S=\left(\cfrac{(5\cdot -14)+(1\cdot 4)}{1+5}\quad ,\quad \cfrac{(5\cdot -1)+(1\cdot -13)}{1+5}\right)$