Question

To find the distance between (-2,-3) and (4,1), Peggy's teacher drew a diagram and marked blue lines to represent the legs of a right triangle. Peggy then used 42 and 62 to find the distance represented by the red segment. What distance did she find ?

Answer 1

Answer:

$d=2\sqrt{13}\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

in this problem we have

$A(-2,-3)\\B(4,1)$  

substitute the values

$d=\sqrt{(1+3)^{2}+(4+2)^{2}}$

$d=\sqrt{(4)^{2}+(6)^{2}}$

$d=\sqrt{52}\ units$

$d=2\sqrt{13}\ units$

Answer 2

Thtas what you must mean. 
The distance beteen th epoints will be sqrt(4^2 + 6^2) = sqrt 52  = 2 sqrt13