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Nesterboy [21]
3 years ago
7

Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur: AX(aq)+BY(aq)→no precipitat

e
Chemistry
1 answer:
Annette [7]3 years ago
6 0
Please rewrite your question and include the following:
1) a question
2) answer choices
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Compare and Contrast the differences between plant animal cells.
sergij07 [2.7K]

Animal cells do not have a cell wall or chloroplasts but plant cells do. Animal cells are mostly round and irregular in shape while plant cells have fixed, rectangular shapes.

8 0
3 years ago
One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that i
vagabundo [1.1K]

Answer:

The value is U  =1.3908 *10^{11} \  kg

Explanation:

From the question we are told that

mass of carbon dioxide produced by one gallon of gasoline is m  =  9.50 \  kg

The number of cars is N =  40 \  million =  40 *10^{6} \  cars

The distance covered by each car is d =  7930 \ mi

The rate is R  =  23.6 \  mi/ gallon

Generally the amount of gasoline used by one car is mathematically represented as

G  =  \frac{d}{R}

=> G  =  \frac{7930}{23.6}

=> G  =   366 \  gallons

Generally the amount of gasoline used by N cars is

H  =  N  *  G

=> H  =  40*10^{6}  *  366

=> H  = 1.464*10^{10} \  gallons

Generally the annual production of carbon dioxide is mathematically represented as

U  =  m *  H

=> U  =9.50 *   1.464*10^{10}

=> U  =1.3908 *10^{11} \  kg

8 0
4 years ago
A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant Kf = 5.32 °C.
Citrus2011 [14]

Answer : The freezing point of a solution is -15.4^oC

Explanation : Given,

Molal-freezing-point-depression constant (K_f) = 5.32^oC/m

Mass of urea (solute) = 29.82 g

Mass of solvent = 500 g  = 0.500 kg

Molar mass of urea = 60.06 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of solvent in Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = ?

\Delta T^o = freezing point of solvent = -10.1^oC

i = Van't Hoff factor = 1 (for urea non-electrolyte)

K_f = freezing point constant = 5.32^oC/m

m = molality

Now put all the given values in this formula, we get

-10.1^oC-T_s=1\times (5.32^oC/m)\times \frac{29.82g}{60.06g/mol\times 0.500kg}

T_s=-15.4^oC

Therefore, the freezing point of a solution is -15.4^oC

5 0
3 years ago
70 POINTS AND BRAINLIEST ASAPPPP
Crank

Answer:

is there anyway u could ut it in diffrent words i do not unders stand

Explanation:

7 0
3 years ago
Please help
Mazyrski [523]

Answer:

Diagram Z

Explanation:

A cell placed into a hypotonic solution will swell and expand until it eventually burst through a process known as cytolysis.

4 0
2 years ago
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