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yaroslaw [1]
2 years ago
14

Please help

Chemistry
1 answer:
Mazyrski [523]2 years ago
4 0

Answer:

Diagram Z

Explanation:

A cell placed into a hypotonic solution will swell and expand until it eventually burst through a process known as cytolysis.

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A student prepares a 0.47mM aqueous solution of acetic acid CH3CO2H. Calculate the fraction of acetic acid that is in the dissoc
Aliun [14]

The fraction of acetic acid that is dissociated is 0.18

Why?

The chemical equation for the dissociation of acetic acid (HAc) is the following:

HAc(aq) + H₂O(l) ⇄ H₃O⁺(aq) + Ac⁻(aq)

To find the fraction of acetic acid that is in the dissociated form (f), we apply the following equation (Ka for acetic acid is 1.76*10⁻⁵). This equation comes from solving the equation of the equilibrium constant for the dissociated fraction of HAc:

f=\frac{-Ka+\sqrt{Ka^{2} +4KaC} }{2C} = 0.18

Have a nice day!

#LearnwithBrainly

6 0
3 years ago
If an equal number of moles of reactants are used, do the following equilibrium mixtures contain primarily reactants or products
puteri [66]

<u>Answer:</u>

<u>For a:</u> The equilibrium mixture contains primarily reactants.

<u>For b:</u> The equilibrium mixture contains primarily products.

<u>Explanation:</u>

There are 3 conditions:

  • When K_{eq}>1; the reaction is product favored.
  • When K_{eq}; the reaction is reactant favored.
  • When K_{e}=1; the reaction is in equilibrium.

For the given chemical reactions:

  • <u>For a:</u>

The chemical equation follows:

HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}

As, K_{eq}, the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

  • <u>For b:</u>

The chemical equation follows:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HCl]^2}{[H_2][Cl_2]}=2.51\times 10^{4}

As, K_{eq}>1, the reaction will be favored on the product side.

Hence, the equilibrium mixture contains primarily products.

4 0
3 years ago
Please help!!! I'll give brainliest to the most helpful answer
horsena [70]
87) A
88) D
89) B
90) E
91) C
3 0
3 years ago
If 4.65 LL of CO2CO2 gas at 22 ∘C∘C at 793 mmHg mmHg is used, what is the final volume, in liters, of the gas at 35 ∘C∘C and a p
otez555 [7]

Answer:

About 7.9 L.

Explanation:

We can utilize the ideal gas law. Recall that:

\displaystyle PV = nRT

Because the amount of carbon dioxide does not change, we can rearrange to formula to:
\displaystyle \frac{PV}{T}= nR

Because the right-hand side stays constant, we have that:
\displaystyle \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = nR

Hence substitute initial values and known final values:
\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ $^\circ$C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ $^\circ$C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}

Therefore, the final volume is about 7.9 L.

8 0
2 years ago
A 500 gram price of metal has a volume of 2.75. What is the density
Oxana [17]
Density of an object is computed by dividing its mass by its volume. D = M / V

Solution:
D = 500 g / 2.75 cm3
D = 181.82 g/cm3

Further, density of an object is computed by dividing its mass by its volume. D = M / V

 However, since Volume is the missing component in the equation. Mass of an object is divided by its density to get its volume. V = M / D

<span>Volume of Gold nugget          = 50 g </span>/<span> 19.3g/cm3  = </span>2.59cm3
<span>Volume of Iron Pyrite nugget = 50 g </span>/ <span>5.0g/cm3    = </span>10cm3

4 0
3 years ago
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