Question

One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that is, it promotes the warming of Earth's atmosphere. Calculate the annual production of carbon dioxide in kilograms if there are exactly 40.0 million cars in the United States and each car covers a distance of 7930 mi at a consumption rate of 23.6 miles per gallon. Enter your answer in scientific notation.

Answer 1

Answer:

The value is $U =1.3908 *10^{11} \ kg$

Explanation:

From the question we are told that

mass of carbon dioxide produced by one gallon of gasoline is $m = 9.50 \ kg$

The number of cars is $N = 40 \ million = 40 *10^{6} \ cars$

The distance covered by each car is $d = 7930 \ mi$

The rate is $R = 23.6 \ mi/ gallon$

Generally the amount of gasoline used by one car is mathematically represented as

$G = \frac{d}{R}$

=> $G = \frac{7930}{23.6}$

=> $G = 366 \ gallons$

Generally the amount of gasoline used by N cars is

$H = N * G$

=> $H = 40*10^{6} * 366$

=> $H = 1.464*10^{10} \ gallons$

Generally the annual production of carbon dioxide is mathematically represented as

$U = m * H$

=> $U =9.50 * 1.464*10^{10}$

=> $U =1.3908 *10^{11} \ kg$